Answer:
A. Answer is 2263.
Checkpoint 1 is -86 Checkpoint 4 is 2177
Subtract -86 from 2177....2177-(-86)
=2263
2263 is how much higher checkpoint 1 (-86) is from checkpoint 4 (2177)
B. 239 FEET.
the altitude of the hill must be subtracted by the depth of the ckeckpoint(2)(-189)
therefore the altitude of the hill comes out to be 428-189=239feet.
therefore,the actual altitude of the hill is 239 feet.
Answer:
3a, 13cm 5, 1:200
Step-by-step explanation:
In the question 3 you just have to divide all of those numbers with that 5000, maybe also make them cm so it makes more sense. So 650m = 65000cm:5000= 13cm
then for the question 5, make the km to cm, so 4.2km would be 420000cm. Then you have to divide that 420000cm with the 21 cm, so 420000:21= 200. Then the scale should be 1:200
I had difficulties with these as well. If you need extra help with the task 3 please pm me :)
3 liters of soda
1.5 pints of sherbet
4.5 cups of ice
To get the answer we can use proportion
220 ----------------95.3%
x -------------------100%
Crossmultiply now
220*100%=95.3%*x
22000=95.3x /:95.3
22000:95.3=x
231=x - its the answer
Answer:
Step-by-step explanation:
From the picture attached,
Statements Reasons
1). In ΔABC, DE intersects AB and AC 1). Given
2). DE║BC 2). Given
3). ∠ADE ≅ ABC 3). Corresponding angles postulate
4). ∠AED ≅ ∠ACB 4). Corresponding angles postulate
5). ΔADE ~ ΔABC 5). AA similarity postulate
6). 
6). Definition of two similar triangles
Hence proved.
