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2 years ago

What is the result when 3/8x + 2 1/5 is subtracted from 3 1/2x - 4 1/10? Don’t put a link.

Mathematics

2 answers:

Umnica [9.8K]2 years ago

6 0

Answer:

Option 3 3 1/8x - 6 3/10

Step-by-step explanation:

(3 1/2x - 4 1/10) - (3/8x + 2 1/5)

Divide it into parts:

(3 1/2x - 3/8x) + (-4 1/10 - 2 1/5)

3 1/2x - 3/8x = 3 4/8x - 3/8x = 3 1/8x

-4 1/10 - 2 1/5 = -4 1/10 - 2 2/10 = -6 3/10

So we get:

2 1/4x - 6 3/10

Setler79 [48]2 years ago

5 0

trying to cheat on a performance matter test but the answer is the last one -3 1/8 x + 6 3/10

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3 years ago

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Which expression shows a way to find 50% of 632

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2 years ago

Rewrite log2^8=3 in exponential form

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3 years ago

I have nooooo clue, please help

Aleksandr-060686 [28]

Answer:

case a) $x^{2}=3y$ ----> open up

case b) $x^{2}=-10y$ ----> open down

case c) $y^{2}=-2x$ ----> open left

case d) $y^{2}=6x$ ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

$y=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

$x=a(y-k)^{2}+h$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

$x^{2}=3y$

$y=(1/3)x^{2}$

$a=(1/3)$

$a>0$

therefore

The parabola open up

case b) we have

$x^{2}=-10y$

$y=-(1/10)x^{2}$

$a=-(1/10)$

$a$

therefore

The parabola open down

case c) we have

$y^{2}=-2x$

$x=-(1/2)y^{2}$

$a=-(1/2)$

$a$

therefore

The parabola open to the left

case d) we have

$y^{2}=6x$

$x=(1/6)y^{2}$

$a=(1/6)$

$a>0$

therefore

The parabola open to the right

3 0

2 years ago