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Svet_ta [14]
2 years ago
6

Can someone help me on this ??

Mathematics
1 answer:
Alenkinab [10]2 years ago
6 0
For the first one it is 1 whole
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-8=2y-3x <br> 4y-12+x=0.
andreyandreev [35.5K]

Answer:

x=4 and y=2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the 11th term of the following geometric sequence.<br> 2, 8, 32, 128, ...
Hitman42 [59]
The 11th term is 2, 095, 152


Explanation:
This is a geometric sequence, since each term after the first is obtained by multiplying a common ratio,
r
.
The common ratio is
4
. The first term,
a
, is
2
. The number of terms,
n
is
11
.
We use the formula
t
n
=
a
×
r
n
−
1
to determine the nth term in a geometric sequence.
t
11
=
2
×
4
11
−
1
t
11
=
2
,
095
,
152
Hopefully this helps!
4 0
3 years ago
Express the limit as a definite integral on the given interval. lim n→[infinity] n xi ln(1 + xi2) Δx, [2, 7] i = 1
xenn [34]

Answer:

Step-by-step explanation:

Consider \  the \ following \ series

\lim_{n \to \infty}  \sum \limits ^n_{i=1} x_i \ In ( 1+ x_i^2) \Delta x , [2,7]

Let's \ recall \ the \ explanation \  of definite \ integral \ in  \ terms  \ of  \ Riemann \ sum

\int^b_a \ f(x) \ dx =  \lim_{n \to \infty}  \sum \limits ^n_{i=1} \ f(x_i) \Delta x , \ where \ \Delta x = \dfrac{b-a}{n}

By  \ efinition,  \ the \  limit \   is \  then \  expressed \   as  \  integral

\lim_{n \to \infty} \sum ^a_{i=1} \ x_i \ In (1+x_i^2) \Delta x = \int^7_2 xIn (1+x^2) \ dx

7 0
2 years ago
Julio tested the point (4, –2) to see whether it is a solution to this system of equations. –3x – 2y = –8, y = 2x – 5 His work i
kolezko [41]

if it is solution point (4, –2) must satisfy both equations
(1) –3x – 2y = –8-->-3*4-2*(-2)=-8
-12+4=-8 then-->-8=-8   ok
(2)  y = 2x – 5
-2=2*4-5=3---------->-2 is not 3

the point  (4, –2) is not solution of the system of equations
6 0
3 years ago
Read 2 more answers
2x - 4 &gt; 4<br> ...................
Veseljchak [2.6K]

Answer:

x>4

Step-by-step explanation:

8 0
3 years ago
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