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Svet_ta [14]
2 years ago
6

Can someone help me on this ??

Mathematics
1 answer:
Alenkinab [10]2 years ago
6 0
For the first one it is 1 whole
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The commutative property of addition states that you can change the order of addends in a sum. The associative property of addit
Anna11 [10]
Commutative:
a+b+c=a+c+b
1.3+23.4+3.4=23.4+1.3+3.4

Associative:   
(a+b)+c=a+(b+c)

(1.3+3.4)+23.4=1.3+(3.4+23.4)
5 0
3 years ago
Find the solution of this system of two linear equations using substitution 11x+3y=103 and y =3x+1
Lesechka [4]
11x+3y=103 and y=3x+1. 

11x+3(3x+1)=103  -----> plug in (3x+1) for y in the first equation.  You will want to distribute the 3 to the 3x+1 to get something that looks like:

11x+9x+3=103    ------> now you want to combine like terms 

20x+3=103 ---> subtract 3 from both sides
20x=100   ----> divide both sides by 20
x=5    

y=3(5)+1     ---> I like to plug in this to the equation that already has y isolated.  3*5 is 15, add 1 and you find that y=16.

(5, 16) will be your final answer (:
8 0
3 years ago
Help on 10 - 15 plss
yawa3891 [41]

Answer:

This is one the situations like "hey ma, I don't know." You should learn to do this yourself and not rely on other digital people. IF I WERE TO HELP YOU, (you should really explain what you need) and the real directions

Step-by-step explanation:

5 0
2 years ago
(11/x^2-25)+(4/x+5)= 3/x-5
Ierofanga [76]
\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
\cfrac{11}{x^2-25}+\cfrac{4}{x+5}=\cfrac{3}{x-5}\implies \cfrac{11}{x^2-5^2}+\cfrac{4}{x+5}=\cfrac{3}{x-5}

\bf \cfrac{11}{(x-5)(x+5)}+\cfrac{4}{x+5}=\cfrac{3}{x-5}\impliedby 
\begin{array}{llll}
\textit{notice, LCD is }(x-5)(x+5)\\
\textit{so let's multiply all by it}\\
\textit{to toss the denominators}
\end{array}

\bf (x-5)(x+5)\left( \cfrac{11}{(x-5)(x+5)}+\cfrac{4}{x+5} \right)=(x-5)(x+5)\left( \cfrac{3}{x-5} \right)
\\\\\\
11+4(x-5)=3(x+5)\implies 11+4x-20=3x+15
\\\\\\
4x-9=3x+15\implies x=24
8 0
3 years ago
At Mike’s favorite coffee shop, the coffee of the day is either a dark roast, a medium roast, or a light roast. From past experi
DaniilM [7]

Answer:

The correct option is d. 0.60

Step-by-step explanation:

Consider the provided information.

At Mike’s favorite coffee shop, the coffee of the day is either a dark roast, a medium roast, or a light roast.

The coffee being a light roast is 0.15 and the probability of the coffee being a dark roast is 0.25.

Pr(Light roast) = 0.15

Pr(Dark roast) = 0.25

We need to find the probability of the coffee of the day not being a light roast or a dark roast on the next day that Mike visits the coffee shop.

Pr(\text{Not being light or dark roast}) =1-Pr(\text{light roast})-Pr(\text{dark roast})

Pr(\text{Not being light or dark roast}) =1-0.15-0.25

Pr(\text{Not being light or dark roast}) =1-0.40

Pr(\text{Not being light or dark roast}) =0.60

Hence, the correct option is d. 0.60

8 0
3 years ago
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