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Greeley [361]
3 years ago
9

Find the values of x and y. X= __ Y= __

Mathematics
1 answer:
azamat3 years ago
6 0

Answer:

x = 20

y = 100

Step-by-step explanation:

To figure out x do this.

3x + 2x = 7x - 40 (collect like terms)

5x = 7x -40 (subtract 7x on both sides)

-2x = -40 (divide by -2 on both sides)

x = 20

Plug in to get y

Since 7x - 40 and y are vertical they equal the same amount

7(20) - 40 = y (multiply 7 by 20)

140 - 40 = y (collect like terms)

100 = y

Hope this helps ya! Keep smiling!

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D) 20 pages in 1/4 minute
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The triangles are congruent by SSS or HL. Triangles M N Q and P Q N are connected at side Q N. Triangle M N Q is rotated about p
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Answer:the last one

Step-by-step explanation:

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Read 2 more answers
Make and test a conjecture about the given quantity.
larisa [96]

Answer:

18. The conjecture is: The product of two negative even integers is an even integer.

Testing: Let integers be -4 and -6. [Two negative even integers]

Then (-4) × (-6) = 24 [Even integer]

19. The conjecture is: Sum of two negative odd integers is a negative even integer.

Testing: Let the two negative odd integers be -3 and -7.

Then -3 + (-7) = -10 is a negative even integer

20. The conjecture is: Sum of two even integers and two odd integers is an even integer.

Testing: Let integers be 4, 12, 13, 17 (Two even integers and two odd integers)

Then 4 + 12 + 13 + 17 = 46 (Even integer)

21. The statement is:  p------->q [If you ran 1 mile, then you ran 5280 feet]

Decide whether statement is true: So if p is True then q is also True.

Hence p------->q is True. So the given statement is True.

Step-by-step explanation:

18. The product of two negative even integers.

Let the integers be -2m and -2n, m and n are positive integers

Product in (-2m) × (-2n) = 4mn = 2(2mn)

= 2p, p = 2mn

The conjecture is: The product of two negative even integers is an even integer.

Testing: Let integers be -4 and -6. [Two negative even integers]

Then (-4) × (-6) = 24 [Even integer]

19. The sum of two negative odd integers.

Let the integers be -(2m + 1) and -(2n + 1), m and n are positive integers

Then -(2m + 1) + [-(2n + 1)] = -2m - 1 - 2n - 1

= -2m - 2n - 2

= -2(+m + 2 + 1)

= -2p, p = m + n + 1

The conjecture is: Sum of two negative odd integers is a negative even integer.

Testing: Let the two negative odd integers be -3 and -7.

Then -3 + (-7) = -10 is a negative even integer

20. The sum of two even integers and two odd integers.

Let the integers be 2m, 2n, 2p + 1, 2q + 1 (m, n, p, q are positive integers)

Then, 2m + 2n + 2p + 1 + 2q + 1 = 2(m + n + p + q + 1)

= 2r, r = m + n + p + q + 1

The conjecture is: Sum of two even integers and two odd integers is an even integer.

Testing: Let integers be 4, 12, 13, 17 (Two even integers and two odd integers)

Then 4 + 12 + 13 + 17 = 46 (Even integer)

21. Let p: You ran 1 mile

Let q: You 5280 feet

The statement is:  p------->q [If you ran 1 mile, then you ran 5280 feet]

Since 1 mile = 5280 feet

So if p is True then q is also True.

Hence p------->q is True. So the given statement is True.

6 0
3 years ago
What is the probability of getting an odd sum of the scores in a throw of two dice?
gogolik [260]
N(s) = 36
n(F) = 18
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that's the answer

Step-by-step explanation:

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