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Greeley [361]
3 years ago
9

Find the values of x and y. X= __ Y= __

Mathematics
1 answer:
azamat3 years ago
6 0

Answer:

x = 20

y = 100

Step-by-step explanation:

To figure out x do this.

3x + 2x = 7x - 40 (collect like terms)

5x = 7x -40 (subtract 7x on both sides)

-2x = -40 (divide by -2 on both sides)

x = 20

Plug in to get y

Since 7x - 40 and y are vertical they equal the same amount

7(20) - 40 = y (multiply 7 by 20)

140 - 40 = y (collect like terms)

100 = y

Hope this helps ya! Keep smiling!

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Please answer this correctly
kupik [55]

Answer:

Look at the money bags below!!! (but I'll give you the answer)

Step-by-step explanation:

John F: 7 full bags - 1 half

Juan A: 9 full bags

Jason A: 3 full bags

Nick J: 3 full bags- 1 half

Alfonso S: 8 full bags

Hope this helped and wasn't confusing!!! xx - Asia

5 0
3 years ago
In a study to establish the absolute threshold of hearing, 80 male college freshmen were each seated in a soundproof room and a
Norma-Jean [14]

Answer:

Step-by-step explanation:

Hello!

To study the threshold of hering the researcher took a random sample of 80 male college freshmen.

The students underwent an audiometry test where a tome was played and they had to press a button when they detected it.  The researcher recorded the lowest stimulus level at which the tone was detected obtaining a sample mean of X[bar]= 22.2 dB and a standard deviation of S= 2.1 dB

To estimate the population mean, since we don't have information about the variable distribution but the sample size is greater than 30, you can use the approximation of the standard normal distribution:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

Where the semiamplitude or margin of error of the interval is:

d= Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

Using a 95% level Z_{0.975}= 1.965

d= 1.965 * \frac{2.1}{\sqrt{80} }

d= 0.46

The point estimate of the population mean of the threshold of hearing for male college freshmen is X[bar]= 22.2 db

And the estimation using a 95%CI is [21.74;22.66]

I hope this helps!

8 0
3 years ago
Can anybody help me or already know the answer to this ? :)
oksian1 [2.3K]
The bottom one is the answer I’m pretty sure ….hope it helps

4 0
3 years ago
Autum school holding a voleturing challeng. Students are encouraged to volunteer for at least 1 1/2 hours per week. Volenteers a
Pani-rosa [81]

Given :

Challenge given is to volunteer for about 1 1/2 hours per week .

Autum did at a rate of 6 3/4 hours per week .

To Find :

The comparison ( ratio )  her volunteers rate with the challenge rate .

Solution :

Simplifying challenge rate in in normal fraction , 1\dfrac{1}{2}=\dfrac{2+1}{2}=\dfrac{3}{2} .

Also , simplifying her rate , 6\dfrac{3}{4}=\dfrac{(6\times 4)+3}{4}=\dfrac{27}{4} .

Now , ratio of his work by challenge is :

R=\dfrac{\dfrac{27}{4}}{\dfrac{3}{2}}\\\\\\R=\dfrac{27\times 2}{4\times 3}\\\\R=\dfrac{9}{2}

Therefore , the ratio is 9/2 or 4 1/2 .

Hence , this is the required solution .

8 0
3 years ago
Read 2 more answers
URGENT HELP !!!!!! answer correctly !!!!! Will be marking Brianliest !!!!!!!!!!!!!
anzhelika [568]

Answer:

(-2, -6)

Step-by-step explanation:

Slope: 1

5 0
3 years ago
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