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Greeley [361]
3 years ago
9

Find the values of x and y. X= __ Y= __

Mathematics
1 answer:
azamat3 years ago
6 0

Answer:

x = 20

y = 100

Step-by-step explanation:

To figure out x do this.

3x + 2x = 7x - 40 (collect like terms)

5x = 7x -40 (subtract 7x on both sides)

-2x = -40 (divide by -2 on both sides)

x = 20

Plug in to get y

Since 7x - 40 and y are vertical they equal the same amount

7(20) - 40 = y (multiply 7 by 20)

140 - 40 = y (collect like terms)

100 = y

Hope this helps ya! Keep smiling!

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The range is the largest number minus the smallest number

10-4

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so 6 is your range

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Explain how to use Pascal's Triangle to expand the binomial (3x-4y)^11
Mars2501 [29]

The solution to the binomial expression by using Pascal's triangle is:

\mathbf{=177147x^{11}-2598156x^{10}y +17321040x^9y^2-69284160x^8y^3+184757760x^7y^4}

\mathbf{-344881152x^6y^5+459841536x^5y^6-437944320x^4y^7+291962880x^3y^8}

\mathbf{-129761280x2y^9+34603008xy^{10}-4194304y^{11}}

<h3>How can we use Pascal's triangle to expand a binomial expression?</h3>

Pascal's triangle can be used to calculate the coefficients of the expansion of (a+b)ⁿ by taking the exponent (n) and adding the value of 1 to it. The coefficients will correspond with the line (n+1) of the triangle.

We can have the Pascal tree triangle expressed as follows:

                          1

               1                   1

        1                2                 1

    1          3              3               1

1      4            6                4            1

--- --- --- --- --- --- --- --- --- --- --- --- --- --- ---

From the given information:

The expansion of (3x-4y)^11 will correspond to line 11.

Using the general formula for the Pascal triangle:

\mathbf{(a+b)^n = c_oa^nb^0 + c_1 a^{n-1}b^1+c_{n-1}a^1b^{n-1}+c_na^0b^n}

The solution to the expansion of the binomial (3x-4y)^11 can be computed as:

\mathbf{=177147x^{11}-2598156x^{10}y +17321040x^9y^2-69284160x^8y^3+184757760x^7y^4}

\mathbf{-344881152x^6y^5+459841536x^5y^6-437944320x^4y^7+291962880x^3y^8}

\mathbf{-129761280x2y^9+34603008xy^{10}-4194304y^{11}}

Learn more about Pascal's triangle here:

brainly.com/question/16978014

#SPJ1

5 0
2 years ago
You cant make your own rectangles
Sliva [168]
Around 7 or 8 I think
6 0
4 years ago
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