Answer:
8 cm
Step-by-step explanation:
the 3 cm line from the chord to the center of a circle is a leg of a right triangle which perpendicularly bisects the chord into two equal halves
draw the hypotenuse of the right triangle from the center of the circle to the endpoint of the chord. This is a radius measuring 5 cm.
find the missing leg of the right triangle
a^2= c^2- b^2
a^2= 25-9
a^2=16
a=4
this is only the measurement of half the chord. To find the full length of the chord multiply by two
4*2=8 cm
Okay, let's see...
The problem is asking for a linear equation most likely in the form of y=mx+b
y is another way to say f(x)
<em>m = slope </em>
<em>b = y intercept </em>
Let's start with the y intercept first.
Y intercept means ' When does the line touch (intercept) the y axis.
In this case, if you look at the graph, the line <em>touches </em>the y axis at -1.
-1 will replaces b
To find the slope we are going to take 2 precise points from the graph.
Lets use <em>(0,-1)</em> and <em>(-6,4) </em>
To find the slope, we're going to use 
4 - (-1) / -6 - 0
Solve, our slope is 5/-6
That is our m
Our final equation is

Answer:
it is 1
Step-by-step explanation:
10 / 1/5 = 50
hope this helps!
Using the number line, the numbers that are 9 units from -5 are: -14 and 4.
<h3>How to Locate a Number on a Number line?</h3>
To find two numbers that cover the same units from a given point on a number line, we can simply do the following:
- Count the number of units given backwards/to the left from the point stated to get the first number.
- Count the number of units given forwards/to the right from the point stated to get the second number.
Thus, we are asked to find the numbers that would be 9 units from -5, using the number line.
Count 9 units backwards/to the left from -5 to get the first number, which is: -14
Count 9 units forwards/to the right from the -5 to get the second number, which is: 4.
Therefore, the numbers that are 9 units from -5 on the number line, are: -14 and 4.
Learn more about number line on:
brainly.com/question/24644930
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