Answer:
299.99 miles
Step-by-step explanation:
Since the plane traveled due west,
The total angle is 49.17 + 90
Represent that with θ
θ = 49.17 + 90
θ = 139.17.
Represent the sides as
A = 170
B = 150
C = unknown
Since, θ is opposite side C, side C can be calculated using cosine formula as;
C² = A² + B² - 2ABCosθ
Substitute values for A, B and θ
C² = 150² + 170² - 2 * 150 * 170 * Cos 139.17
C² = 22500 + 28900 - 51000 * Cos 139.17
C² = 51400 - 51000 (−0.7567)
C² = 51400 + 38,591.7
C² = 89,991.7
Take Square Root of both sides
C = 299.9861663477167
C = 299.99 miles (Approximated)
Hence, the distance between the plane and the airport is 299.99 miles
Answer:
that is the equation of the line, its slope is 1 and the y-intercept is 1 y = x + 1
Step-by-step explanation:
we can calculate the slope of this line passing through (4,5) and (8,9) like this:
m = (y2 - y1)/(x2 - x1)
m = (9 - 5)/(8 - 4)
m = 4/4
m = 1
so the slope is 1, and now we can use the equation of one point and the slope to write the line's equation:
y - y1 = m(x - x1)
y - 5 = 1*(x - 4)
y - 5 = x - 4
y = x + 1
that is the equation of the line, its slope is 1 and the y-intercept is 1
Answer:
Step-by-step explanation:
D 30 would be the answer sorry if its wrong
(7x^2-2) - (2x^2 - 5x + 3)
Answer:
5(x^2+x-1)