Answer:
2.28% probability that a person selected at random will have an IQ of 110 or greater
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or greater?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.9772
1 - 0.9772 = 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or greater
Answer:
a. 14
b. 28
Step-by-step explanation:
a. ex: (6+3)2 - 4 = 9(2) - 4
18 - 4 = <u>14</u>
b. ex: 23 + (14 - 4) / 2
Use PEMDAS
P 1st
10
D over A
5
A
<u>28</u>
<em><u>Hope this helps!</u></em>
Answer: 7824537630
Step-by-step explanation:
The answer is y=34
Explanation:
Answer:
116 cm²
Step-by-step explanation:
The area of a circle = πr² ← r is the radius
shaded area = external area - internal area
= π × 6.5² - π × 2.3²
= π( 42.25 - 5.29)
= π × 36.96 ≈ 116 cm²