Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.
This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.
34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
1.9
32 in - 31.2 in
and that to the left of 32 in is z = ---------------------- = 0.421
1.9
Know how to use a table of z-scores to find these two areas? If not, let me know and I'll go over that with you.
My TI-83 calculator provided the following result:
normalcdf(32, 34, 31.2, 1.9) = 0.267 (answer to this sample problem)
Answer:
Second Man = (2 Hours * 1.3333 Hours) / (2 Hours - 1.3333 Hours)
Second Man = (2.6666666667 ) / (.666666667)
Second Man (when working alone) = 4 Hours
Step-by-step explanation:
3^2 = 9
9/9 = 1
1 + 12 = 13
This is based on the Order of Operations.
Hope it helps! :D
Answer:
A
Step-by-step explanation:
It's a solid dot that's going left, so it's less than or equal to. What integer is it on? -2. So it is either less than or equal to -2.
The total loss is 84 loss (-84).
