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just olya [345]
3 years ago
14

How do i evaluate it????

Mathematics
1 answer:
Kitty [74]3 years ago
4 0

Answer:

1 for all evaluate questions

Step-by-step explanation:

just remember anything to the zero power is 1

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The image is below (I MARK BRAINLIEST)
Sedaia [141]

Answer:

option a

Step-by-step explanation:

7 0
2 years ago
Order the numbers from least to greatest. 8, 0, -8, -3, 5
Kitty [74]

Answer:

-8,-3,0,5,8

Step-by-step explanation:

Number the the negatives from greatest to least first and continue to number the positives from least to greatest.

7 0
3 years ago
In a group of 90 seventh
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90 x .80= 72. 72 Students like hot choco, therefore 8 do no like hot choco
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2 years ago
Read 2 more answers
Consider the differential equationy′′+3y′−10y=0.(a) Find the general solution to this differential equation.(b) Now solve the in
RSB [31]

Answer:

Y= 2e^(5t)

Step-by-step explanation:

Taking Laplace of the given differential equation:

s^2+3s-10=0

s^2+5s-2s-10=0

s(s+5)-2(s+5) =0

(s-2) (s+5) =0

s=2, s=-5

Hence, the general solution will be:

Y=Ae^(-2t)+ Be^(5t)………………………………(D)

Put t = 0 in equation (D)

Y (0) =A+B

2 =A+B……………………………………… (i)

Now take derivative of (D) with respect to "t", we get:

Y=-2Ae^(-2t)+5Be^(5t)   ....................... (E)

Put t = 0 in equation (E) we get:

Y’ (0) = -2A+5B

10  = -2A+5B ……………………………………(ii)

2(i) + (ii) =>

2A+2B=4 .....................(iii)

-2A+5B=10 .................(iv)

Solving (iii) and (iv)

7B=14

B=2

Now put B=2 in (i)

A=2-2

A=0

By putting the values of A and B in equation (D)

Y= 2e^(5t)

6 0
3 years ago
Solve the system of equations. −9y+4x−20=0−7y+16x−80=0\begin{aligned} &-9y+4x - 20=0 \\\\ &-7y+16x-80=0 \end{aligned} ​
gulaghasi [49]

Answer:

  • (x, y) = (5, 0)

Step-by-step explanation:

\begin{aligned} &-9y+4x - 20=0 \\ &-7y+16x-80=0 \end{aligned}

Subtract 4 times the first equation from the second:

  (-7y +16x -80) -4(-9y +4x -20) = (0) -4(0)

  29y = 0 . . . . . simplify

  y = 0 . . . . . . . .divide by 29

  4x -20 = 0 . . . . substitute 0 for y in the first equation

  x -5 = 0 . . . . . .divide by 4

  x = 5 . . . . . . . . add 5

The solution to this system is (x, y) = (5, 0).

7 0
3 years ago
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