Answer:
Area of the other polygon = 4 in.²
Step-by-step explanation:
Area of the bigger polygon : Area of the smaller polygon = square of the side length of the bigger polygon : square of the corresponding side length of the smaller polygon
Let "x" represent the area of the smaller polygon
Thus, we have:
100/x = 20²/4²
100/x = 400/16
100/x = 25
Cross multiply
25x = 100
Divide both sides by 25
25x/25 = 100/25
x = 4
Area of the other polygon = 4 in.²
Answer:
47.25 ft³
Step-by-step explanation:
The volume of the prism is given by the formula ...
V = Bh . . . . . . . B is the area of the base, h is the height.
The height of the prism is given as 6 ft. The area of the base is the area of the triangular entrance. The formula for that area is ...
A = 1/2bh . . . . . . b is the base, h is the height
Using the given values for the entrance base and height, we get ...
A = 1/2(4.5 ft)(3.5 ft) = 7.875 ft²
Then the volume of the tent is ...
V = (7.875 ft²)(6 ft) = 47.25 ft³
The tent volume is 47.25 cubic feet.
I think we're not supposed to do more than 3 problems in one answer; certainly not five pages. Does the 1/3 mean there are 10 more to come?
I'll do the first page.
6)
Right triangle, opposite side of 10, adjacent side of 21,
tan x = opp/adj = 10/21
x = arctan 10/21 = 25.46°
Answer: 25
7)
cos x = adj / hyp = 10/14
x = arccos 10/14 = 44.42°
Answer: 44
8)
tan x = opp/adj = 12/24 = 1/2
x = arctan 1/2 = 26.57°
Answer: 27
9)
tan x = 31/32
x = arctan 31/32 = 44.09°
Answer: 44
10)
x = arctan 10/27 = 20.32°
Answer: 20
= (a-5).(a+3)
= a²+3a-5a-15
= a²-2a-15
Answer:
57.5
Step-by-step explanation:
The expected frequency of West Campus and Failed :
Let :
Failed = F
East Campus = C
West Campus = W
Passed = P
Frequency of FnW :
[(FnE) + (FnW) * (PnW) + (FnW)] / total samples
[(52 + 63) * (63 + 37)] / 200
[(115 * 100)] / 200
11500 / 200
= 57.5
n(Failed n East campus)