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Semenov [28]
3 years ago
5

The diagonals of a quadrilateral must be bisect each other and be perpendicular to gurarantee that the quadrilateral is a parrel

ogram
Mathematics
1 answer:
morpeh [17]3 years ago
4 0

Answer:

False

Step-by-step explanation:

A quadrilateral is a closed geometrical figure that have four sides and four vertices. Thus the following includes in a quadrilateral : parallelogram, square, rhombus, rectangle and trapezium.

If the diagonals of the quadrilateral bisects each other and are perpendicular to each other, then the quadrilateral forms a rhombus.

Hence the answer is FALSE.

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PLEASE HELP!!!
rosijanka [135]

Answer:

Area of the other polygon = 4 in.²

Step-by-step explanation:

Area of the bigger polygon : Area of the smaller polygon = square of the side length of the bigger polygon : square of the corresponding side length of the smaller polygon

Let "x" represent the area of the smaller polygon

Thus, we have:

100/x = 20²/4²

100/x = 400/16

100/x = 25

Cross multiply

25x = 100

Divide both sides by 25

25x/25 = 100/25

x = 4

Area of the other polygon = 4 in.²

8 0
3 years ago
Please help with this!!!
ehidna [41]

Answer:

  47.25 ft³

Step-by-step explanation:

The volume of the prism is given by the formula ...

  V = Bh . . . . . . . B is the area of the base, h is the height.

The height of the prism is given as 6 ft. The area of the base is the area of the triangular entrance. The formula for that area is ...

  A = 1/2bh . . . . . . b is the base, h is the height

Using the given values for the entrance base and height, we get ...

  A = 1/2(4.5 ft)(3.5 ft) = 7.875 ft²

Then the volume of the tent is ...

  V = (7.875 ft²)(6 ft) = 47.25 ft³

The tent volume is 47.25 cubic feet.

8 0
2 years ago
Please help me i am desperate please (1/3)
Sergeu [11.5K]

I think we're not supposed to do more than 3 problems in one answer; certainly not five pages. Does the 1/3 mean there are 10 more to come?

I'll do the first page.

6)

Right triangle, opposite side of 10, adjacent side of 21,

tan x = opp/adj = 10/21

x = arctan 10/21 = 25.46°

Answer: 25

7)

cos x =   adj / hyp = 10/14

x = arccos 10/14 = 44.42°

Answer: 44

8)

tan x = opp/adj = 12/24 = 1/2

x = arctan 1/2 = 26.57°

Answer: 27

9)

tan x = 31/32

x = arctan 31/32 = 44.09°

Answer: 44

10)

x = arctan 10/27 = 20.32°

Answer: 20

8 0
3 years ago
What is the product of (a-5) and (a+3)
abruzzese [7]
= (a-5).(a+3) = a²+3a-5a-15 = a²-2a-15
3 0
2 years ago
In order to determine if there is a significant difference between campuses and pass rate, the chi-square test for association a
RUDIKE [14]

Answer:

57.5

Step-by-step explanation:

The expected frequency of West Campus and Failed :

Let :

Failed = F

East Campus = C

West Campus = W

Passed = P

Frequency of FnW :

[(FnE) + (FnW) * (PnW) + (FnW)] / total samples

[(52 + 63) * (63 + 37)] / 200

[(115 * 100)] / 200

11500 / 200

= 57.5

n(Failed n East campus)

5 0
2 years ago
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