Make the 3 into a fraction and then flip it to cancel out which makes it easier then do it to the -2,197 for you to get x
Answer:
30.91% probability that the islanders will win exactly one out of four games in a series against the rangers
Step-by-step explanation:
For each game, there are only two possible outcomes. Either the Islanders win, or they do not. The probability of the Islanders winning a game is independent of other games. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
The probability that the islanders will beat the rangers in a game is 0.44
This means that 
What is the probability that the islanders will win exactly one out of four games in a series against the rangers?
This is P(X = 1) when n = 4. Then


30.91% probability that the islanders will win exactly one out of four games in a series against the rangers
Answer: 42.9%
Step-by-step explanation:
Percent error is the difference between the measured and known value, which is divided by the known value, and then multiplied by 100%.
Percent error = (Estimated number- Actual number)/Actual Number × 100.
= (60 - 42)/42 × 100
= 18/42 × 100
= 0.429 × 100
= 42.9%
Answer:
B
Step-by-step explanation:
Answer:
a) 22497.7 < μ< 24502.3
b) With 99% confidence the possible error will not exceed 1002.3
Step-by-step explanation:
Given that:
Mean (μ) = 23500 kilometers per year
Standard deviation (σ) = 3900 kilometers
Confidence level (c) = 99% = 0.99
number of samples (n) = 100
a) α = 1 - c = 1 - 0.99 = 0.01

Using normal distribution table,
is the z value of 1 - 0.005 = 0.995 of the area to the right which is 2.57.
The margin of error (e) is given as:

The 99% confidence interval = (μ - e, μ + e) = (23500 - 1002.3, 23500 + 1002.3) = (22497.7, 24502.3)
Confidence interval = 22497.7 < μ< 24502.3
b) With 99% confidence the possible error will not exceed 1002.3