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Leona [35]
2 years ago
15

I NEED HELP ASAP ! PLS!

Mathematics
2 answers:
snow_lady [41]2 years ago
7 0
Your welcome person you get brainliest
amm18122 years ago
5 0

Answer:

x = 106°

Step-by-step explanation:

sum of interior opposite angles of a triangular is equal to a exterior angle

= x +22= 40 +88

= x = 128- 22

x = 106 °

hope this answers will be helpful for you and plzzz mark my answer as brainlist plzzzz vote me also.....

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adelina 88 [10]
3. you cannot simplify √30
4 0
2 years ago
I’m giving all the points I have, plz help and get it right? Someone please help me
Feliz [49]

Answer:

The area (probability) is: 0.6864.

Step-by-step explanation:

According to the statement, we are in front of a normal distribution with the following parameters:

µ (mean) = 0

σ (Standard deviation) = 1.

Then we need to find the area of the shaded region, which is the area between the points -1.21 < z < 0.84.

And the area (probability) is: 0.6864.

3 0
3 years ago
Read 2 more answers
How much is 3 x4x5x6x7x9
Xelga [282]
3x4=12 12x5=60 60x6=360 360x7=2,530 2,530x9=22,690
4 0
3 years ago
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0
3 years ago
A line passes through the point (-7,8) and has a slope of 1
Mila [183]

Answer:

y - 8 = x + 7

Step-by-step explanation:

To write the equation of a line use the point slope form. Substitute m = 1 and (-7,8).

y - y_1 = m(x-x_1)\\y - 8 = 1(x --7)\\y - 8 = 1(x + 7)\\y - 8 = x+7

3 0
3 years ago
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