You have to solve this algebraicly.
To do this set up the proportion and add x to each term.
You get 4x and 7x
Set this equal to 33
4x+7x=33
Combine like terms and get 11x=33
Divide by 11
x=3
Now go back to 4x and 7x
Multiply them by x and get 12(4×3=12) and 21(7×3=21)
One group is 12 and the other is 21.
Answer:
(-4,4)
Step-by-step explanation:
-5x-10y=-20
10x+10y=0
divide both sides by 2
-5x-10y=-20
5x+5y=0
that makes
-5y=-20
divide both sides by -5
y=4
now substitute 4 for y
10x+10 x 4=0
multiply
10x+40=0
subtract
10x=-40
divide
x=-4
3x^4 + 5x - 6x^2 + 10x^3....in descending order
3x^4 + 10x^3 - 6x^2 + 5x
coefficients are : 3,10,-6,5
4.) 3/100 = 0.03
5.) 73% = 0.73
6.) 0.1 = 10%
7.) 254% = 2.54
I hope this is what you're looking for!
-72yexponet73 + 2xexponet2 :)
