3 years ago

Can you please help meeeeeeee

Mathematics

1 answer:

Ahat [919]3 years ago

4 0

The outlier would be 68

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charle [14.2K]

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3 years ago

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Simplify the expression. (81x^12/3x^3)^1/3

ser-zykov [4K]

Raise each number to the power outside the parentheses.

$\left( \dfrac{81x^{12}}{3x^3} \right) ^{ \frac{1}{3} } = \\

= \left( 27x^{12-3} \right) ^{ \frac{1}{3} } = \\

= \left( 27x^{9} \right) ^{ \frac{1}{3} } = \\

= \left( 3^3x^{9} \right) ^{ \frac{1}{3} } = \\

= \left( 3^3 \right) ^{ \frac{1}{3} } \times \left( x^{9} \right) ^{ \frac{1}{3} } \\

= \left( 3^{3 \times \frac{1}{3} } \right) \times \left( x^{9 \times \frac{1}{3} }} \right) \\

= 3^1 x^3 \\

= 3x^3


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