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ololo11 [35]
3 years ago
5

So you have 21 people that you want to have meet in groups of 3. How many rounds of meeting would it take to have them all meet?

Mathematics
1 answer:
irina1246 [14]3 years ago
8 0

Answer:

1330 rounds of meetings

Step-by-step explanation:

You have a total of 21 people, and  they all want to meet with each other in groups of 3. This means we are dealing with a combination problem, where combination is the selection of items in which order does <em>not</em> matter.

Formula for combination:

ₙCᵣ = \frac{n!}{r!(n-r)!}

where <em>n</em> is the total number of objects (in this case, total number of people: 21), and r is the sample set (in this case, groups: 3).

We plug in and get:

-> \frac{21!}{3!(21-3)!}

-> 1330 different meetings for everyone to meet with each other in groups of 3.

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