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galina1969 [7]
3 years ago
6

An automobile owner has 40% chance of having exactly one accident in a year and 60% chance of having no accidents in a year. The

re is no chance that the automobile owner incurs more than one accident in a year.
If there is an accident, the loss amount has the following distribution:
Loss Amount Probability
30 0.30
60 0.15
100 0.45
180 0.10
Suppose there is an ordinary deductible of $40 and the maximum payment by the insurer is $130.
Determine the standard deviation of the payment made by the insurer to the automobile owner.
A: 32.44
B: 33.60
C: 34.77
D: 26.78
E: 27.43
Mathematics
1 answer:
sergey [27]3 years ago
6 0

Answer:

A. 32.44

Step-by-step explanation:

Automobile owner has 40% chance for one accident in a year and 60% of zero accident in a year.

Let x is the loss of accident and y is the payment by insurer.

Y = 0 if X < 40,

x - 40 if 40 < x < 130

130 if x \geq 170

Then, Var [y] = E y^2

Var [y] = 1052.16

E = 32.437.

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The mean of three numbers is 8 two of the numbers are 6 and 11 work out the third number
Andreas93 [3]

Answer:

7

Step-by-step explanation:

To find the number, first multiply 8 by 3, since that is how you find the mean.

8 x 3 = 24 (total)

x + 6 + 11 = 24

x = 24 - 6 - 11

x = 7

Inverse:

7 + 6 + 11 = 24

Mean = 24/3 = 8

Hope this helps!

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3 years ago
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Step-by-step explanation:

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7 0
3 years ago
Isabella save 2 nickels today, if she doubles the number of Nicole, she saves every day, how many days, including today, will it
Elden [556K]

Answer:

  8 days

Step-by-step explanation:

On day 8, Isabella will save 256 nickels, bringing her total to 510.

_____

The number of nickels saved on day n is 2^n. The total is 2^(n+1)-2.

_____

The above can be written down from your knowledge of binary sequences. If you want a more formal development, read on.

__

The number of nickels saved on day n is a geometric sequence with first term 2 and common ratio 2. The n-th term of the sequence is ...

  an = a1·r^(n-1) = 2·2^(n-1) = 2^n

The sum of n terms of the sequence is ...

  S = a1(r^n -1)/(r -1) = 2(2^n -1)/(2-1)

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__

We want S > 500, so ...

  500 < 2^(n+1) -2

  502 < 2^(n+1)

  251 < 2^n

  log(251) < n·log(2)

  n > log(251)/log(2)

  n > 7.97 . . . . . . . . 8 days or more to save more than 500 nickels

3 0
4 years ago
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