PLEASE EXPLAIN! Please explain this. Not just give answer. Solve each exponential equation using Logarithms.

Naddik [55]

Step 1 Find the least common denominator
Step 2 Find the equivalent fractions
Step 3 Add or subtract the whole numbers
Step 4 write your answer in lowest terms

3 0

3 years ago

Read 2 more answers

Solve the following equation. Then place the correct number in box provided.

Pepsi [2]

x is equal to 0 because 6 is already equal to 6

so there shouldnt be another number unless its 0

0+6=6

7 0

2 years ago

Solve.<br><br> The answer must be a fraction. Solve by substituting.

maw [93]

Answer: x = -14/5

Step-by-step explanation: We shall begin by expanding the brackets for both sides of the equation

-2/3 (x + 2) = 1/6 (x + 6)

(-2x/3) -4/3 = (x/6) + 1

By collecting like terms we now have

(-2x/3) - (x/6) = 1 + 4/3

(-4x - x)/6 = 7/3

-5x/6 = 7/3

By cross multiplication we now have

-5x (3) = 7 (6)

-15x = 42

x = -(42/15) {simplify further by dividing the RHS by 3}

x = -14/5

Therefore x equals, minus fourteen over five (-14/5)

4 0

2 years ago

What is the approximate area of the figure?

melisa1 [442]

Option D:

The approximate area of the figure is 109.6 square feet.

Solution:

The figure is splitted into three shapes.

One is rectangle and the other two is semi-circles.

Diameter of the semi-circle = 5 feet

Radius of the semi-circle = 5 ÷ 2 = 2.5 feet

Area of the semi-circle = $\frac{1}{2}\pi r^2$

$$=\frac{1}{2}\times 3.14\times (2.5)^2$

Area of the semi-circle = 9.8 square feet

Area of 2 semi-circles = 2 × 9.8

Area of 2 semi-circles = 19.6 square feet

Length of the rectangle = 18 feet

Width of the rectangle = 5 feet

Area of the rectangle = length × width

= 18 × 5

Area of the rectangle = 90 square feet

Area of the figure = Area of 2 semi-circles + Area of the rectangle

= 19.6 square feet + 90 square feet

= 109.6 square feet

The approximate area of the figure is 109.6 square feet.

Hence Option D is the correct answer.

4 0

2 years ago

Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.

kolezko [41]

Answer:

$A=4.5u^2$

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

$y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3$

$y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9$

The integral will be the subtraction of the curve $y=3x$ and $y=x^2$ (In the graph you can see y=3x is the upper curve):

$\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2$

6 0

2 years ago