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2 years ago

3/7 divided by 6 please help google isn’t

Mathematics

2 answers:

Mrac [35]2 years ago

5 0

Answer:

1/14 Hope this helps!!! :) Have a great day

Step-by-step explanation:

Blizzard [7]2 years ago

3 0

Answer:

1/14

Step-by-step explanation:

3/7 × 1/6

1/7 × 1/2

1/14

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Awnser in one/two step equations

solniwko [45]

-6=-7+x

Make the variable to the left hand side and change it’s sign.

-6-x=-7

Move the constant to the right hand side and change its sign.

-x=-7+6

Calculate the sum

-x=-1

Change the signs of both sides of the equation .

X=1

5 0

2 years ago

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What is 2/42 simplified?

olga_2 [115]

It would be simplified to 1/21

6 0

3 years ago

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Question in Picture<br> vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

Crank

Answer:

Angle BOC = 28; Angle AOB = 21

Step-by-step explanation:

Because angle AOC = AOB + BOC you can set the equation:

2x+10 + 4x-15 = 49

6x - 5 = 49

6x = 54

x= 9

BOC = 2(9) +10 = 28

AOB = 4(9) - 15 = 21

6 0

3 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago

I need help very fast plz someone help

jarptica [38.1K]

Answer:

4-9=-5

Step-by-step explanation:

do the work you get that

6 0

3 years ago

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