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3 years ago

What is the median. I have 3 more questions that have to deal with the median.

Mathematics

1 answer:

Rom4ik [11]3 years ago

6 0

Answer:

Step-by-step explanation:

Median - The middle number in a list of numbers starting from least to greatest.

Knowing this, we can start.

The first step is to rewrite all the numbers from least to greatest

15, 19, 28, 32, 43, 52, 66, 72, 72, 81

Now cross off a number from the least and greatest until there is 1 or 2 numbers left

19, 28, 32, 43, 52, 66, 72, 72

28, 32, 43, 52, 66, 72

32, 43, 52, 66

43, 52

If you are left we 1 number, that is your answer. If you are left with 2 numbers, there is an extra step

In the case that you have 2 numbers, you need to add them together, and divide by 2

43 + 52 = 95

95 ÷ 2 = 47.5

Thus 47.5 is our answer

You might be interested in

What is 12 hours made into minutes

OleMash [197]

12 hours converted into minutes is: 720 minutes

We know that 1 hour is converted into 60 minutes, so to get 12 hours converted into 720 minutes, multiplication comes in handy when doing this.

Every hour includes of 60 minutes each. Times the 12 hours you're converting with 60 minutes.

12 × 60 = 720

4 0

3 years ago

Read 2 more answers

Please help with number 3!! I can’t figure it out.

FrozenT [24]

Answer:

Gabe worked 65, Abe worked 62 and Babe worked 69.

Step-by-step explanation:

Let Gabe = x

Therefore, Abe worked: x-3 and Babe worked x+4

So,

x+(x-3)+(x+4)=196

3*x+1=196

3*x=195

x=65

Then,

x-3= 62

x+4=69

8 0

3 years ago

After school, Emily had a science club meeting for 40 minutes, followed by a choir rehearsal

aniked [119]

Answer:

3:15 pm

Step-by-step explanation:

(1:25 + 40 min) = 2:05 + 75 min= 3:15

7 0

3 years ago

A sequence is defined by the recursive function f(n+1)=f(n). If f(3)=9, what is f(1)?

vekshin1

Put n=2 ,
f(2+1) = f(2) => f(3) = f(2) = 9
now, put n=1,
f(1+1) = f(1) => f(2) = f(1) = 9

6 0

3 years ago

Read 2 more answers

Suppose that a cyclist began a 476

mojhsa [17]

Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus $\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{eastbound cyclist}&d&r&8.5\\
\textit{westbound car}&476-d&r+33.2&8.5
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
\boxed{d}=8.5r\\\\
476-d=(r+33.2)8.5\\
----------\\
476-\boxed{8.5r}=(r+33.2)8.5
\end{cases}$

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2

6 0

3 years ago