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GaryK [48]
3 years ago
15

What is the median. I have 3 more questions that have to deal with the median.

Mathematics
1 answer:
Rom4ik [11]3 years ago
6 0

Answer:

<h2><u>47.5</u></h2>

Step-by-step explanation:

Median - The middle number in a list of numbers starting from least to greatest.

Knowing this, we can start.

The first step is to rewrite all the numbers from least to greatest

15, 19, 28, 32, 43, 52, 66, 72, 72, 81

Now cross off a number from the least and greatest until there is 1 or 2 numbers left

19, 28, 32, 43, 52, 66, 72, 72

28, 32, 43, 52, 66, 72

32, 43, 52, 66

43, 52

If you are left we 1 number, that is your answer. If you are left with 2 numbers, there is an extra step

In the case that you have 2 numbers, you need to add them together, and divide by 2

43 + 52 = 95

95 ÷ 2 = 47.5

Thus 47.5 is our answer

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hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20

Compute the probability that a randomly selected component needs rework as follows:

P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069}  =0.3623

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

6 0
2 years ago
Find the inverse of each function. h ( n ) = 4/n − 2
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Step-by-step explanation:

Add similar elements: -5x+3x=-2x

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-2x + 15-15=-3-15

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Divide both sides by -2

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Answer:

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2 years ago
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