Explanation:
a. The line joining the midpoints of the parallel bases is perpendicular to both of them. It is the line of symmetry for the trapezoid. This means the angles and sides on one side of that line of symmetry are congruent to the corresponding angles and sides on the other side of the line. The diagonals are the same length.
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b. We observe that adjacent pairs of points have the same x-coordinate, so are on vertical lines, which have undefined slope. KN is a segment of the line x=1; LM is a segment of the line x=3. If the trapezoid is isosceles, the midpoints of these segments will be on a horizontal line. The midpoint of KN is at y=(3-2)/2 = 1/2. The midpoint of LM is at y=(1+0)/2 = 1/2. These points are on the same horizontal line, so the trapezoid <em>is isosceles</em>.
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c. We observed in part (b) that the parallel sides are KN and LM. The coordinate difference between K and L is (1, 3) -(3, 1) = (-2, 2). That is, segment KL is the hypotenuse of an isosceles right triangle with side lengths 2, so the lengths of KL and MN are both 2√2.
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For part (c), we used the shortcut that the hypotenuse of an isosceles right triangle is √2 times the leg length.
Answer:
Therefore the THREE roots are
Step-by-step explanation:
Given:
To Find:
All the Roots = ?
Solution:
As the degree of the polynomial is THREE then the number of root are also THREE.
Now one root is Zero For other we need to Factorize
So by Splitting the middle term
i.e Factor of 12 such that sum should be 7
i.e 3 × 4 = 12 and 3 + 4 = 7
∴
Therefore the THREE roots are
Answer:
30.7 km
Step-by-step explanation:
The distance between the two fires can be found using the Law of Cosines. For ΔABC in which sides 'a' and 'b' are given, along with angle C, the third side is ...
c = √(a² +b² -2ab·cos(C))
The angle measured between the two fires is ...
180° -(69° -35°) = 146°
and the distance is ...
c = √(11² +21² -2(11)(21)cos(146°)) ≈ √945.015
c ≈ 30.74
The straight-line distance between the two fires is about 30.7 km.
Step-by-step explanation: