Well as x can never actually be -1 because I'm in the denominator -1 + 1 = 0 and we cannot divide by zero. But we can look at what number it approaches and i assume that is the relative value. sometimes functions will have asymptotes and others will have holes in the graph. this one would have an asymptote going down at a rapid rate. the asymptote would go on forever getting infinitely close to -1 but never touching. So I would say since the asymptote goes down forever that the graph approaches negative infinity

6 0

3 years ago

Question 9 of 10 Which of these groups of values plugged into the TVM Solver of a graphing calculator will return the same value

hodyreva [135]

The TVM solver is a tool found in graphing calculators, that solve Time Value of Money problems.

The group of values that will return the same value as the given expression is;

D. N = 24; I% = 3.6; PV =; PMT = -415; FV = 0; P/Y = 12; C/Y = 12; PMT :END

<h3>What is Present Value?</h3>

Present value (PV) formula finds application in finance to calculate the present day value of an amount that is received at a future date.

In the TVM solver, we have;

I = The annual percentage rate

N = n × t

t = The number of years

PV = Present value

PMT = Payment

P/Y = Number of payments per year = n

C/Y = Number of compounding periods per year = n

The formula for monthly payment is presented as follows;

$P = \frac{M[(1+r/n)^{nt} - 1]}{(r/n)(1+r/n)^{nt}}$

M = $\frac{P.(r/n)(1+ r/n)^{nt} }{(1+ r/n)^{nt} - 1}$

Therefore, we get;

Where;

M = PMT = -415

P = PV

r = I

P/Y = n = 12

Therefore;

0.003 = I/12

I = 0.003 X 12 = 3.6%

N = n X t = 24

The value of the equation is the present value, PV = ?

When payment are made based on the PV, we have FV = 0

The group of values the same value as the expression

P = $\frac{(415)[(1+0.003)^{24}-1]}{(0.003)(1+0.003)^{24}}$

when plugged into the TVM solver of a calculator is;

D. N = 24; I% = 3.6; PV =; PMT = -415; FV = 0; P/Y = 12; C/Y = 12; PMT :END

Learn more about Present Value Solver from:

brainly.com/question/1759639

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7 0

2 years ago