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4 years ago

What’s 6 times 251 in expanded form? HELP!!

Mathematics

2 answers:

kramer4 years ago

8 0

Answer:

1506

Step-by-step explanation:

1,506 = (1 x 1000) + (1 x 00) + (0 x 0) + (6 x 1)

BaLLatris [955]4 years ago

6 0

That hat would be 1,506

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D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago

Use the diagram to complete the statements.

Ksenya-84 [330]

Answer: The answers are: 3, 4, point R to point Q, depression from point Q to point R

Step-by-step explanation:

4 0

3 years ago

PLZ HELP ANSWER BY TODAY

Ivahew [28]

X = 29

Explanation:

Rigt angle means 90°

Here 2x + 32 = 90

so, 2x = 90 - 32

2x = 58

x = 58÷2

x = 29

7 0

3 years ago

9 430 000 000 000 km in standard form

mote1985 [20]

9.43 x 10^12 is the answer

8 0

3 years ago

Suppose the function h(x)=2x-9 is translated up 5 united to become a new function, i(x). what the equation of the new function?

andreyandreev [35.5K]

Option B

i(x) = 2x - 4 is the equation of the new function

Solution:

Given that the function h(x) = 2x-9 is translated up 5 united to become a new function, i(x)

To find: Equation of new function

The graph of a function can be moved up, down, left, or right by adding to or subtracting from the output or the input.

Adding to the output of a function moves the graph up

Therefore,

Given function is:

h(x) = 2x - 9

Translated up by 5 units

Therefore, new function is:

i(x) = h(x) + 5

i(x) = 2x - 9 + 5

i(x) = 2x - 4

Thus Option B is correct

6 0

4 years ago