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OlgaM077 [116]
3 years ago
12

How would you balance this chemical equation?

Chemistry
1 answer:
frutty [35]3 years ago
8 0

Answer:

CH4 + 4Cl2 ===> CCl4 + 4HCl

Explanation:

If you are having trouble understanding how to balance equations, use chemical equation calculators and they tell you step by step.

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The two major classes of telescopes are the _____ and the _____ telescope.
sukhopar [10]

Answer:

refractors and reflectors

Explanation:

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Alkaline are great for long-term use in a device, such as in a digital camera or game console remote. Carbon zinc batteries are ideal in a situation where one needs to power multiple devices for one occasion, such as when buying many toys during the Christmas season to be used for a few days.

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3 years ago
Read 2 more answers
In which way does a balanced chemical equation demonstrate the conservation of matter?
777dan777 [17]

Answer:

A. It shows the same number of atoms of each element on both sides of the equation.

Explanation:

A balanced chemical equation demonstrates the conservation of matter by showing the number of atoms of each element on both sides of the equation or expression.

According to the law of conservation of matter, matter is neither created nor destroyed in the course of a chemical reaction but atoms are rearranged.

  • Based on this premise, the number of atoms or moles on both sides of the expression must be equal.
  • If there are 3 atoms of carbon on one side, the product must also reflect 3 atoms of carbon.
8 0
3 years ago
50.g of NaNO3 was dissolved in 1250 mL of water. what is the molality of the solution? [ Molar mass of NaNO3 = 85 g/mol
Viefleur [7K]

Answer:

Approximately 0.47\; \rm mol \cdot L^{-1} (note that 1\; \rm M = 1 \; \rm mol \cdot L^{-1}.)

Explanation:

The molarity of a solution gives the number of moles of solute in each unit volume of the solution. In this \rm NaNO_3 solution in water,

Let n be the number of moles of the solute in the whole solution. Let V represent the volume of that solution. The formula for the molarity c of that solution is:

\displaystyle c = \frac{n}{V}.

In this question, the volume of the solution is known to be 1250\; \rm mL. That's 1.250\; \rm L in standard units. What needs to be found is n, the number of moles of \rm NaNO_3 in that solution.

The molar mass (formula mass) of a compound gives the mass of each mole of units of this compound. For example, the molar mass of \rm NaNO_3 is 85\; \rm g \cdot mol^{-1} means that the mass of one mole of

\displaystyle n = \frac{m}{M}.

For this question,

\begin{aligned}&n\left(\mathrm{NaNO_3}\right) \\ &= \frac{m\left(\mathrm{NaNO_3}\right)}{M\left(\mathrm{NaNO_3}\right)}\\&= \frac{50\; \rm g}{85\; \rm g \cdot mol^{-1}} \\& \approx 0.588235\; \rm mol\end{aligned}.

Calculate the molarity of this solution:

\begin{aligned}c &= \frac{n}{V} \\&= \frac{0.588235\; \rm mol}{1.250\; \rm L} \\&\approx 0.47\;\rm mol \cdot L^{-1}\end{aligned}.

Note that 1\; \rm mol \cdot L^{-1} (one mole per liter solution) is the same as 1\; \rm M.

8 0
3 years ago
How many particles would be found in a 12.7 g sample of ammonium carbonate? Show workkk
Sophie [7]

Answer:

7.8286×10²¹ particles

Explanation:

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3 0
3 years ago
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