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erik [133]
3 years ago
6

Please Help NO LINKS

Mathematics
1 answer:
schepotkina [342]3 years ago
3 0

V = 864\pi

Step-by-step explanation:

Since one of the boundaries is y = 0, we need to find the roots of the function f(x)=-2x^2+6x+36. Using the quadratic equation, we get

x = \dfrac{-6 \pm \sqrt{36 - (4)(-2)(36)}}{-4}= -3,\:6

But since the region is also bounded by x = 0, that means that our limits of integration are from x=0 (instead of -3) to x=6.

Now let's find the volume using the cylindrical shells method. The volume of rotation of the region is given by

\displaystyle V = \int f(x)2\pi xdx

\:\:\:\:\:\:\:= \displaystyle \int_0^6 (-2x^2+6x+36)(2 \pi x)dx

\:\:\:\:\:\:\:= \displaystyle 2\pi \int_0^6 (-2x^3+6x^2+36x)dx

\:\:\:\:\:\:\:= \displaystyle 2\pi \left(-\frac{1}{2}x^4+2x^3+18x^2 \right)_0^6

\:\:\:\:\:\:\:= 864\pi

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