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never [62]
3 years ago
12

I will give BRAINLIEST to the first correct answer THANKYOUUU!!!

Mathematics
1 answer:
Bas_tet [7]3 years ago
8 0

Answer:no clue

Step-by-step explanation:

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Evaluate 4x when x = -9
Strike441 [17]

SOLUTION

In this question, we are meant to evaluate 4 x when x = -9.

4 x = 4 X -9 = -36

7 0
2 years ago
Which equation represents the line that passes through the points (-1,-2)and(3,10)
aalyn [17]

Answer:

Step-by-step explanation:

(-1,-2) , (3,10)

slope(m) = (10 - (-2) / (3 - (-1) = (10 + 2) / (3 + 1) = 12/4 = 3

y = mx + b

slope(m) = 3

u can use either of ur points....

(3,10)....x = 3 and y = 10

sub into the formula and find b, the y int

10 = 3(3) + b

10 = 9 + b

10 - 9 = b

1 = b

so ur equation is : y = 3x + 1

3 0
3 years ago
2x-4y=8 and 7x-3y=61 solve by substitution
Ratling [72]

Answer:

(10, 3)

Step-by-step explanation:

Solve by Substitution

2x − 4y = 8 and 7x − 3y = 61

Solve for x in the first equation.

x = 4 + 2y 7x − 3y = 61

Replace all occurrences of x with 4 + 2y in each e quation.

Replace all occurrences of x in 7x − 3y = 61 with 4 + 2y. 7 (4 + 2y) − 3y = 61

x = 4 + 2y

Simplify 7 (4 + 2y) − 3y.

28 + 11y = 61

x = 4 + 2y

Solve for y in the first equation.

Move all terms not containing y to the right side of the equation.

11y = 33

x = 4 + 2y

 Divide each term by 11 and simplify.

y = 3

x = 4 + 2y

 

Replace all occurrences of y with 3 in each equation.

Replace all occurrences of y in x = 4 + 2y with 3. x = 4 + 2 (3)

y = 3

Simplify 4 + 2 (3).

x = 10

y = 3

The solution to the system is the complete set of ordered pairs that are valid solutions.

(10, 3)

The result can be shown in multiple forms.

Point Form:

(10, 3)

Equation Form:

x = 10, y = 3

4 0
3 years ago
Read 2 more answers
Select all the rational numbers.
Otrada [13]

Answer:

56, 6.56, 0.23, -538 are the rational numbers

5 0
3 years ago
The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is
Ray Of Light [21]
Part A;
There are many system of inequalities that can be created such that only contain points A and E in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, -3) and (3, 1) but is not satisfied by (-3, -4), (-4, 2), (2, 4) and (-2, 3) can serve.

An example of such system of equation is
y ≤ x
y ≥ -2x
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the line y = -2x and to the right of the line y = x is shaded.



Part B:
It can be verified that points A and E are solutions to the system of inequalities above by substituting the coordinates of points A and E into the system of equations and see whether they are true.

Substituting A(2, -3) into the system we have:
-3 ≤ 2
-3 ≥ -2(2) ⇒ -3 ≥ -4
as can be seen the two inequalities above are true, hence point A is a solution to the set of inequalities.

Also, substituting E(3, 1) into the system we have:
1 ≤ 3
1 ≥ -2(3) ⇒ 1 ≥ -6
as can be seen the two inequalities above are true, hence point E is a solution to the set of inequalities.



Part C:
Given that William can only attend a school in her designated zone and that William's zone is defined by y < −x - 1.

To identify the schools that William is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining William's zone.

For point A(2, -3): -3 < -(2) - 1 ⇒ -3 < -2 - 1 ⇒ -3 < -3 which is false

For point B(-3, -4): -4 < -(-3) - 1 ⇒ -4 < 3 - 1 ⇒ -4 < 2 which is true

For point C(-4, 2): 2 < -(-4) - 1 ⇒ 2 < 4 - 1 ⇒ 2 < 3 which is true

For point D(2, 4): 4 < -(2) - 1 ⇒ 4 < -2 - 1 ⇒ 4 < -3 which is false

For point E(3, 1): 1 < -(3) - 1 ⇒ 1 < -3 - 1 ⇒ 1 < -4 which is false

For point F(-2, 3): 3 < -(-2) - 1 ⇒ 3 < 2 - 1 ⇒ 3 < 1 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point B and C.
4 0
3 years ago
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