Answer:
The instantaneous rate of change of with respect to at the value is 18.
Step-by-step explanation:
a) Geometrically speaking, the average rate of change of with respect to over the interval by definition of secant line:
(1)
Where:
, - Lower and upper bounds of the interval.
, - Function exaluated at lower and upper bounds of the interval.
If we know that , and , then the average rate of change of with respect to over the interval is:
The average rate of change of with respect to over the interval is 27.
b) The instantaneous rate of change can be determined by the following definition:
(2)
- Change rate.
, - Function evaluated at and .
If we know that and , then the instantaneous rate of change of with respect to is:
The answer is (X +2)^2 = 4(Y -5).
Range is (-8,00)
10.31 pounds
First, we multiply 1.3 x 2 because he is gaining 1.3 for the next TWO weeks.
1.3 x 2 = 2.6
Now, add 7.71 + 2.6 because that is the weight he started with.
7.71 + 2.6 = 10.31
Her brother will weight 10.31 pounds if he is 7.71 lbs and continues to gain 1.3 pounds each week for two weeks.