Answer:
2x^2 +2x-4
——————
2x^2-4x+2
Factor out 2 from the expression
2(x^2+x-2)
—————-
2(x^2-2x+1)
Write x as a difference
2(x^2x-x-2)
—————-
2(x^2-2x+1)
Use a^2-2ab+b^2=(ab)^2
2(x^2x-x-2)
—————-
2(x-1)^2
Reduce the fraction with 2
x^2x-x-2
—————-
(x-1)^2
Factor out x from the expression
X*(x^2)-x-2
—————-
(x-1)^2
Factor out negative sign from the expression
X*(x+2)-(x-2)
—————-
(x-1)^2
Factor out x+2 from the expression
(x+2)(x-1)
—————-
(x-1)^2
Simplify the expression
x+2
——
x-1
Answer:
-40
Step-by-step explanation:
f(a) = a³ - a² + a - 1
f(-3) = (-3)³ - (-3)² + (-3) - 1
f(-3) = (-27) - (9) + (-3) -1
f(-3) = -27 - 9 -3 - 1
f(-3) = -40
Answer:
r5 tj rhe 62hs fgus us reallh bard lil
Answer:
$1.75
Step-by-step explanation:
The selling for each candy bar may be determined by a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.
It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation
.
Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25
23s + 36c = 114.75
37s + 36c = 146.25
14s = 31.5
s = $2.25
23(2.25) + 36c = 114.75
36c = 114.75 - 51.75
36c = 63
c = 63/36
= $1.75
I think it’s B. 7.50+1.50x<_15
