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UkoKoshka [18]
3 years ago
14

What are all the common factors of 9 and 18

Mathematics
2 answers:
Kobotan [32]3 years ago
8 0
♥ Common factors of 9:
<span>1, 3, 9
</span>♥ Common factors of 18 are:
<span>1, 2, 3, 6, 9, 18
</span>The Greatest Common Factor:
=9
You can find the greatest common factor by looking at the highest point in each factor.
The highest in 9 is 9 and 9 is in 18 and that is the highest of 9 therefore its the highest total. 
ipn [44]3 years ago
6 0
Are 1, 3, 9
...........................
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Step-by-step explanation:

0.378 \times 100, 000 \\  = 37 800

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I need help with coming up with equation
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Let's call a child's ticket c and an adult's ticket a. From this, we can say:

c + a = 116,

since 116 tickets are sold in total.


Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus

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17000a + 12750c = 1653250,

since each adult ticket a costs 17,000 and each child's ticket c costs 12,750, and these costs sum to 1,653,250.


Now, we have two equations:

17000a + 12750c = 1653250

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Let's solve:

17000a + 12750c = 1653250

a = 116 - c

  • Find a on its own, which will allow us to substitute it into the first equation

17000(116 - c) + 12750a = 1653250

  • Substitute in 116 - c for a

1972000 - 17000c + 12750c = 1653250

  • Apply the Distributive Property

1972000 - 4250c = 1653250

  • Combine like terms

4250c = 318750

  • Subtract 1972000 from both sides of the equation and multiply both sides by -1

c = 75


We have now found that 75 child's tickets were sold. Thus,

75 + a = 116 \Rightarrow a = 116 - 75 = 41,

41 adult tickets were sold as well.


In sum, 41 adult tickets were sold along with 75 child tickets.

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3 years ago
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3 years ago
Read 2 more answers
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