Answer: The two sides are 15m and 10m.
Step-by-step explanation:
Area = l x w
150 = l x w
There are two solutions for l
l 1= P/4+1/4√P2﹣16A
=50/4+1/4·√50^2﹣16·150=15m
l2 = P/4﹣1/4√P2﹣16A
=50/4﹣1/4·√50^2﹣16·150=10m
No, because negative base sometimes results in non-real or imaginary value.
Answer:
- <em> 15</em>
- <em> 42,250</em>
Step-by-step explanation:
The given function is,
![P=40000+300x-10x^2](https://tex.z-dn.net/?f=P%3D40000%2B300x-10x%5E2)
where,
P = the total production of apples,
x = the number of trees added.
As the quadratic function has a negative leading coefficient, so it will open downward and at the vertex the value of function is maximum.
The vertex will be at ![\left(-\dfrac{b}{2a},-f\left(\dfrac{b}{2a}\right )\right)](https://tex.z-dn.net/?f=%5Cleft%28-%5Cdfrac%7Bb%7D%7B2a%7D%2C-f%5Cleft%28%5Cdfrac%7Bb%7D%7B2a%7D%5Cright%20%29%5Cright%29)
The value of the function will be maximum at,
![x=-\dfrac{b}{2a}](https://tex.z-dn.net/?f=x%3D-%5Cdfrac%7Bb%7D%7B2a%7D)
Putting the values,
![x=-\dfrac{300}{2\times (-10)}=\dfrac{300}{2\times 10}=\dfrac{300}{20}=15](https://tex.z-dn.net/?f=x%3D-%5Cdfrac%7B300%7D%7B2%5Ctimes%20%28-10%29%7D%3D%5Cdfrac%7B300%7D%7B2%5Ctimes%2010%7D%3D%5Cdfrac%7B300%7D%7B20%7D%3D15)
So at x=15 or for 15 number of trees the production will be ,maximum.
Putting x=15 in f(x) will yield the maximum production of apples.
![P=40000+300(15)-10(15)^2=42,250](https://tex.z-dn.net/?f=P%3D40000%2B300%2815%29-10%2815%29%5E2%3D42%2C250)
Answer:
n = 13
Step-by-step explanation:
24 = 3 (n-5)
3n - 15 = 24
3n = 24 +15
3n = 39
n = 39/3
n = 13
Answer:
w = 2 cm
Step-by-step explanation:
100 = 25 x 2 x w
w = 2 cm