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3 years ago

What will the finance charge be on Hannah's computer purchase? (Do not include sales tax)

Mathematics

1 answer:

k0ka [10]3 years ago

8 0

Answer:

She would be paying $2,622 total.

Step-by-step explanation:

1. To get how much she'd be paying for 24 months, all you have to do is multiply 24 times 95.

2. To get the down payment you had to ask yourself what's 15% of 2,280. 15% of 2280 is 342.

3. Add those together and you'd get the total payment.

Simple.

Oh and gimme Brainliest if it's correct.

You might be interested in

Given the arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103,...

omeli [17]

We are given

arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103

so, first term is 124

u(1)= 124

now, we can find common difference

$d=u(2)-u(1)$

$d=117-124$

$d=-7$

now, we can find kth term

$u(k)=u(1)+(k-1)d$

now, we can plug values

and we get

$u(k)=124+(k-1)*-7$

$u(k)=124-7k+7$

$u(k)=131-7k$

u(k) must be negative

so,

$u(k)=131-7k$

$131-7k$

now, we can solve for k

$7k>131$

$k>18.714$

so, it's closest integer value is

$k=19$ ..............Answer

3 0

4 years ago

Is ( 0,0) a solution to this system? y<=x^2-4 y>2x-1?

Xelga [282]

Answer:

The point $(0,0)$ is not a solution of the system of inequalities

Step-by-step explanation:

we have

$y\leq x^{2} -4$ -----> inequality A

$y> 2x-1$ -----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities

then

the ordered pair must be satisfy the inequalities of the system

Verify

For $x=0, y=0$

substitute the value of x and the value of y in the inequalkity A and in the inequality B

Inequality A

$0\leq 0^{2} -4$

$0\leq -4$ -------> is not true

therefore

The point $(0,0)$ is not a solution of the system of inequalities

3 0

3 years ago

Read 2 more answers

Find the product and fill in the blanks to write in standard complex number form

k0ka [10]

X^2 +2x +10 = 0

D = 4 -40 = - 36

x_1,2 = (-2 +/- sqrt(-36))/2 = (-2 +/- 6i)/2 = 2(-1 +/- 3i)/2 = -1 +/- 3i

x_1,2 = -1 +/- 3i or more understandably

x_1 = -1 -3i and x_2 = -1 +3i

hope this will help you

3 0

3 years ago

Jasmine has a bag of 48 peanuts. She eats 3/4 of the bag during the baseball game. How many peanuts does she have left? Explain

rosijanka [135]

Answer:

Step-by-step explanation:

If she eats 3/4 of the bag, that means she has 1-3/4 = 4/4 -3/4 = 1/4 of the bag left

The bag has 48 nuts. Take the number of nuts times the 1/4 she has left

48 * 1/4 = 12

She has 12 nuts left

7 0

3 years ago

A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w

sveta [45]

Answer:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for business

$\hat p_A =\frac{75}{400}=0.1875$ represent the estimated proportion for Business

$n_A=400$ is the sample size required for Business

$p_B$ represent the real population proportion for non Business

$\hat p_B =\frac{137}{500}=0.274$ represent the estimated proportion for non Business

$n_B=500$ is the sample size required for non Business

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

7 0

3 years ago