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3 years ago

If the graph f(x)= 9x^2+36x+41/3x+5 has an oblique asymptote at y=3x+k what is the value of k

Mathematics

2 answers:

Galina-37 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Gelneren [198K]3 years ago

5 0

Answer:

The value of k is 7.

Explanation:

To find the oblique asymptote of a rational function you divide the numerator by the denominator and take the quotient (not the remainder).

Such quotient (without the remainder) is the equation of the line that is the oblique asymptote of the rational function.

The rational function is:

$\frac{9x^2+36x+41}{3x+5}$

You can see the long division in the picture attached. The quotient is 3x + 7.

Hence, by comparison with y = 3x + k, k = 7.

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-3r + 7 - 3r - 12 in simplest form

Akimi4 [234]

Since the co-efficient or "r" is "-3" and "-3", it will simplify to "-6" as -3-3= -6.
then the two constant terms with are "7" and "-12" will simplify to "-5" as 7-12=-5. therefore, the simplest form is -6r -5

hope it helped!

8 0

3 years ago

Around balloon has a diameter of 7 3/8 inches which of the following is closest to the number of cubic inches of Air can hold it

k0ka [10]

Answer:

Step-by-step explanation:

It might not be F. I think it is though

5 0

3 years ago

Divide each polynomials by the monomials. Choose all that are correct. (9xy2 + 12x3y4 − 6x) ÷ 3x = 4x2y4 + 3y2 − 2 (25x4y2 + 10x

UkoKoshka [18]

Answer:

(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy

Step-by-step explanation:

(9xy^2 + 12x^3y^4 − 6x) ÷ 3x = 4x^2y^4 + 3y^2 − 2 (False: 9xy^2:3x=3y^2)

25x^4y^2 + 10x^2y^4 − 15y) ÷ 5y = 5x^4y + 2x^3y^2 − 3 (False: 10x^2y^4:5y=2x^2y^3)

(16x^4y^2 + 24x^2y^2 − 8xy^2) ÷ 4xy = 4x^4y + 6xy− 2y(False: 16x^4y^2:4xy=4x^3y)

(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy (True)

7 0

3 years ago

15/16 divided by 3/4 = ?

Dmitry [639]

5/4

(15/16)(4/3) The 4/3 is the reciprocal of 3/4

=5/4

8 0

3 years ago

Help geom !! Transformation!

elixir [45]

Answer:

Step-by-step explanation:

Rotating 120

4 0

3 years ago