Answer:
1. Group A and B agree with each other.
2. Group A and C do not agree with each other.
Step-by-step explanation:
When we are analizing this problem, we will see what are the ranges of this measured times. Since we are taking into account the error we can see that :
- Group A varies from 7.34-0.05 to 7.34+0.05. So the limits are (7.29 ;7.39)
- Group B varies from 7.38-0.03 to 7.38+0.03. So the limits are (7.35; 7.41)
- Group C varies from 7.46-0.06 to 7.46+0.06. So the limits are (7.40; 7.52)
Question 1 is about the overlapping response in Group A and Group B. And yes, we have an overlap between 7.35 to 7.39. Among this times both group A and B are in agree with each other within the experimental uncertainty.
Question 2 is now referring to Group A and Group C. And no, there isn't any common time where both groups agree with each other.
Answer:
- 83 1/3 ft wide
- 171 2/3 ft long
Step-by-step explanation:
Let w represent the width of the area. Then 2w+5 represents the length. The perimeter is twice the sum of length and width:
P = 2(L+W)
510 = 2(2w+5 +w) . . substitute given values
255 = 3w +5 . . . . . . divide by 2
250 = 3w . . . . . . . . . subtract 5
83 1/3 = w . . . . . . . . .divide by 3; the width of the area
2w+5 = 171 2/3 . . . . the length of the area
The fenced area is 83 1/3 ft wide and 171 2/3 ft long.
Answer:
F(x) = x^3 and G(x) = (4x)^3 − 5
so
G(x) = F(4x) -5
the visual effect is
1) shrink horizontally by 1/4
2) shift down by 5
therefore
the answer is the option
D.The graph of G(x) is the graph of F(x) compressed horizontally and shifted 5 units down.
Step-by-step explanation:
Answer: z=-190
Step-by-step explanation:
