The probability that he selected the special quarter is 87.5%.
<h3><u /></h3><h3><u>Probability</u></h3>
Given that Mandvil has one standard quarter and one special quarter with a Head on both sides, and he selects one of these two coins at random, and without looking at it first, he flips the coin three times, to determine, if he flips a Head three straight times, what is the probability that he selected the special quarter, the following calculation must be made:
- 1 - (standard quarter) = X
- 1 - (0.50^3) = X
- 1 - 0.125 = X
- 0.875 = X
- 0.875 x 100 = 87.5
Therefore, the probability that he selected the special quarter is 87.5%.
Learn more about probability in brainly.com/question/24217562
<span>The cosine of pi/2 is 0 so the problem really says "find the angle between - pi/2 and pi/2 whose tan = 0. That would be the same as asking for the angle whose sin is 0. That would be 0.
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Convert the feet to inches first. 2 ft = 24 inches. We must divide this total length by the length of each tile to determine how many tiles will fit across the tabletop:
24 ÷ (1/4) = (24/1) ÷ (1/4) = (24/1) × (4/1) = 96/1 = 96
96 tiles will fit across the tabletop.
Since the tabletop is as long as it is wide, that means we will have 96 rows of 96 tiles:
96(96) = 9,216 tiles to cover the tabletop.
Answer:
Step-by-step explanation:
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