B. The total cost (1) after 8% sales tax is added to an item's price (p): 1.08p =

What adds to give you 1, but multiplies to give you -90?

ella [17]

I would say -9 and 10

4 0

3 years ago

How do you solve a function

madreJ [45]

You used to say "y = 2x + 3; solve<span> for y when x = –1". Now you say "f(x) = 2x + 3; find f(–1)" (pronounced as "f-of-x is 2x plus three; find f-of-negative-one"). You do exactly the same thing in either case: you plug in –1 for x, multiply by 2, and then add the 3, simplifying to get a final value of +1.
Brainliest?</span>

7 0

3 years ago

please help me i will mark brainliest!!! Rewrite as a simplified fraction 0.612 also the 12 is repeating

Aleksandr [31]

Answer:

= 68/111

Step-by-step explanation:

4 0

2 years ago

Q3: Identify the graph of the equation and write and equation of the translated or rotated graph in general form. (Picture Provi

natta225 [31]

Answer:

b. circle; $2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

Step-by-step explanation:

The given conic has equation;

$x^2-5x+y^2=3$

We complete the square to obtain;

$(x-\frac{5}{2})^2+(y-0)^2=\frac{37}{4}$

This is a circle with center;

$(\frac{5}{2},0)$

This implies that;

$x=\frac{5}{2},y=0$

When the circle is rotated through an angle of $\theta=\frac{\pi}{3}$ ,

The new center is obtained using;

$x'=x\cos(\theta)+y\sin(\theta)$ and $y'=-x\sin(\theta)+y\cos(\theta)$

We plug in the given angle with x and y values to get;

$x'=(\frac{5}{2})\cos(\frac{\pi}{3})+(0)\sin(\frac{\pi}{3})$ and $y'=--(\frac{5}{2})\sin(\frac{\pi}{3})+(0)\cos(\frac{\pi}{3})$

This gives us;

$x'=\frac{5}{4} ,y'=\frac{5\sqrt{3} }{4}$

The equation of the rotated circle is;

$(x'-\frac{5}{4})^2+(y'-\frac{5\sqrt{3} }{4})^2=\frac{37}{4}$

Expand;

$(x')^2+(y')^2-\frac{5\sqrt{3} }{2}y'-\frac{5}{2}x'+\frac{25}{4} =\frac{37}{4}$

Multiply through by 4; to get

$4(x')^2+4(y')^2-10\sqrt{3}y'-10x'+25 =37$

Write in general form;

$4(x')^2+4(y')^2-10x'-10\sqrt{3}y'-12 =0$

Divide through by 2.

$2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

8 0

3 years ago

A random sample of 78 eighth grade students' scores on a national mathematics assessment test has a mean score of 284.

oksian1 [2.3K]

Answer:

a) In the step-by-step-explanation

b) z(s) = -2.46 corresponding area is 0.0069

P [ μ₀ > 275 ] is 0.0069 or 0.69 %

We reject H₀

Step-by-step explanation:

Normal distribution

Random sample

size sample 78 = n

population standard deviation σ = 32

The school administrator declare that mean score is more (bigger than)

275. So the hypothesis test should be:

H₀ null hypothesis μ₀ > 275 and

Hₐ alternative hypothesis μ₀ < 275

Is one tail test with α = 0,04 from tables we have z(c) = - 176

We proceed to compute z(s)

z(s) = [ (μ - μ₀) /( σ /√n) ] ⇒ z(s) = (- 9 *√78 )/ 32

z(s) = - (9*8.83)/32

z(s) = - 2.46 corresponding area is 0,0069

P [ z > 275 ] = 0.0069 or 0.69 %

The value for z(s) = - 2.46 is smaller than the critical value mentioned in problem statement z(c) = - 1.74 , the z(s) is in the rejection zone

Therefore we reject H₀

6 0

3 years ago