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sergij07 [2.7K]
3 years ago
15

using the table below give 3 scenarios in real life where you can apply the lesson that you have studied.​

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

Mathematics lesson

Step-by-step explanation:

Algebra and 3D, D-Shapes

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What is 12% added to $1.78
cestrela7 [59]
1.9$ would be the answer for this question
5 0
3 years ago
select yes or no to indicate if a rectangle with the given dimensions whould have a perimeter of 50 inches
umka21 [38]
1a) no it would be 54

1b) yes

1c) yes

1d) no it would be 40

1e) yes



hope this helped
8 0
3 years ago
Find the equation of the line with a slope of 1/5 that passes through the point (10,9).
IRINA_888 [86]

Answer:

The equation of the line with a slope of 1/5 that passes through the point (10,9) is:

  • y=\frac{1}{5}x+7

Step-by-step explanation:

Given

Slope = m = 1/5

Point (10, 9)

To Determine

An equation of the line with a slope of 1/5 that passes through the point (10,9).

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

substituting the values m = 1/5 and the point (10, 9) in the equation

y-y_1=m\left(x-x_1\right)

y-9=\frac{1}{5}\left(x-10\right)

Add 9 to both sides

y-9+9=\frac{1}{5}\left(x-10\right)+9

y=\frac{1}{5}x-2+9

y=\frac{1}{5}x+7

Therefore, the equation of the line with a slope of 1/5 that passes through the point (10,9) is:

  • y=\frac{1}{5}x+7
3 0
3 years ago
Hellllllllllllllp. this scale drawing of a desktop
Kruka [31]
So the since the length of the longer side is 45inches we know that the longer table is 5 times as larger than the small desktop. And we know 6 x 5 = 30.
So 45x30= 1,350 so the answer is 1,350 square inches! :)
6 0
4 years ago
Read 2 more answers
Find the limit of the following sequence or determine that the limit does not exist. {5n/Squareroot 81 n^2 + 5} Select the corre
elixir [45]

Answer:

C. The sequence is monotonic and bounded. The limit is 5/9

Step-by-step explanation:

For this case we have the following n term:

a_n = \frac{5n}{\sqrt{81n^2 +5}}

And we can find the limit when x tend to infinity:

\lim_{n\to\infty} \frac{5n}{\sqrt{81n^2 +5}}

And we got this:

5 \lim_{n\to\infty} \frac{n}{\sqrt{81n^2 +5}}

Now we can divide by n the numerator and denominator like this:

5 \lim_{n\to\infty} \frac{1}{\sqrt{81 +\frac{5}{n^2}}}

And now we can apply properties of limits and we got this:

5 \frac{\lim_{n\to\infty} 1}{\lim_{n\to\infty} \sqrt{81 +\frac{5}{n^2}}}

And we got:

5 \frac{1}{9}=\frac{5}{9}

So then our sequence is bounded by \frac{5}{9}

By definition a monotonic sequence is a "sequence that is always increasing or decreasing".

For this case if we find:

a_1 = \frac{5}{\sqrt{86}}

a_2 = \frac{10}{\sqrt{329}}

We see that a_2 >a_1 and in general we see that a_n >a_{n-1}. So then the ebst answer for this case is:

C. The sequence is monotonic and bounded. The limit is 5/9

7 0
4 years ago
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