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murzikaleks [220]
3 years ago
9

Find the lenght of the missing side:

Mathematics
2 answers:
Reika [66]3 years ago
8 0

Answer:

15.73

Step-by-step explanation:

cos(x) = adjacent leg / hypotenuse

cos(70) = x / 46

0.342 = x / 46

0.342 x 46 = x

x = 15.73

ollegr [7]3 years ago
7 0

Answer:

x=15.73292

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj/ hyp

cos 70 = x / 46

46 cos 70 =x

x=15.73292

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Gabby bought 5.15 kg of apples and 1.6 kg of oranges how much fruit did she buy in all
solmaris [256]

Answer:

6.75kg of fruit

Step-by-step explanation:

5 + 1 = 6

.15 + .6 = .75

6 + .75 = 6.75

8 0
4 years ago
Read 2 more answers
in all, how many counting numbers from 200 to 500 are divisible by all of the following 2, 3, 4,5 and 6?
Arte-miy333 [17]

Answer:

I think its  6 numbers  . See below

Step-by-step explanation:

The numbers must end in 0 because they must be divisible by 2 and 5

240 is one number it is the first number between 200 and 500 which is divisible by the 5 numbers.

The LCM of the 5 numbers is  60 so we can add  300, 360, 420 and 480 to the list.

5 0
3 years ago
Decreasing 3/4 times a number by 18 is equal to increasing 1/2 times the number by 5 give an equation and solution to the situat
Maslowich

Answer:

92

Step-by-step explanation:

Let the number be x.

As per the question,

3/4x - 18 = 1/2x + 5

(4)3/4x - (4)18 = (4)1/2x + (4)5

3x - 72 = 2x + 20

x = 92

The number is 92.

7 0
2 years ago
Read 2 more answers
When Alexandria was born, her length was in the 96th percentile
nadezda [96]

Answer:

4) About 96% of newborn girls were the same length as Alexandria.

Step-by-step explanation:

3 0
3 years ago
What is the probability that a five-card poker hand contains exactly one ace?.
spin [16.1K]

The probability of selecting exactly one ace is its likelihood

The probability that a five-card poker hand contains exactly one ace is 29.95%

<h3>How to determine the probability?</h3>

There are 4 aces in a standard deck of 52 cards.

The probability of selecting an ace would be:

p = 4/52

Also, there are 48 non-ace cards in the standard deck

So, the probability of selecting a non-ace after an ace has been selected is:

p = 48/51

The probability of selecting a non-ace up to the fifth selection are:

  • After two cards have been selected is:  47/50.
  • After three cards have been selected is:  46/49.
  • After four cards have been selected is:  45/48.

The required probability is then calculated as:

P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)

Where n is the number of cards i.e. 5

So, we have:

P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)

Evaluate

P(1 Ace) = 0.2995

Express as percentage

P(1 Ace) = 29.95%

Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%

Read more about probability at:

brainly.com/question/25870256

8 0
3 years ago
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