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3 years ago

12

Hari earns Rs 4300 per month. He spends 80% from his income. How much does he save in a year? please give answer in step by ste

p explaination

1 answer:

timofeeve [1]3 years ago

8 0

Answer:

4300 x 12= 51600

20/100 x 51600

10,320 Rs (also pay bohat kam hai :D )

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.) A store receives 8 boxes of picture frames to sell. Unfortunately, 3 of the frames are broken and cannot be sold. There are 4

Mars2501 [29]

Answer:

There are 6 boxes

Step-by-step explanation:

We know there are 45 frames and 3 broken ones, so there are 48 frames in total.

We know there are 8 boxes that have the frames.

let x equal the amount of picture frames in a box

8x=48

8x/8 = 48/8

x=6

5 0

3 years ago

If you run 1/2 miles on Friday, 2/3 of a mile Saturday, how many miles will you run on sunday

Natasha_Volkova [10]

Answer:

3/4

Step-by-step explanation:

because it goes 1-2 then 2-3 so then 3-4

8 0

3 years ago

1. 400 +4<br> 2. 320+ 4<br> 3. 360 +9<br> 4. 5,0005<br> 5. 3,000 +5

Liono4ka [1.6K]

Answer:

1. 400 ÷ 4 = 100

2. 320 ÷ 4 = 80

3. 360 ÷ 9 = 40

4. 5000 ÷ 5 = 1000

5. 3000 ÷ 5 = 600

6 0

3 years ago

Read 2 more answers

The coordinates of the endpoints of ST are (-2,3) and (3, y) respectively supposethe distance between s and t us 13 units.What v

igor_vitrenko [27]

Answer:

The values of y would be -9 and 15

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$d=13\ units$

S(-2,3) and T(3,y)

substitute the given values in the formula and solve for y

$13=\sqrt{(y-3)^{2}+(3+2)^{2}}$

$13=\sqrt{(y-3)^{2}+25}$

squared both sides

$169=(y-3)^{2}+25$

$(y-3)^{2}=169-25$

$(y-3)^{2}=144$

take square root both sides

$y-3=(+/-)12$

$y=3(+/-)12$

$y=3(+)12=15$

$y=3(-)12=-9$

therefore

The values of y would be -9 and 15

5 0

4 years ago

Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel

Nataliya [291]

Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e ( $x_o, y_o, z_o$ ) and are parallel to $\dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}$

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

$x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct$

x = 4 + t

y = -5 + 2t

z = 2 + t

Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

$\begin {vmatrix} x = 4+ t \\ \\ \dfrac{x-4}{1} = t \begin {vmatirx} \end {vmatrix}$ $\begin {vmatrix} y = - 5+2t \\ \\ \dfrac{y+5}{2} =t \end {vmatrix}$ $\begin {vmatrix} z =2+t \\ \\ \dfrac{z-2}{1} =t \end {vmatrix}$

∴

$\dfrac{x-4}{1}= \dfrac{y+5}{2}=\dfrac{z-2}{1}$

8 0

3 years ago