Answer:
210, 211, 212
Step-by-step explanation:
If we denote the first number as x, then the second number can be written as x + 1 and the third number as x + 2.
The equation is:
x + (x + 1) + (x + 2) = 633
3x + 3 = 633
3x = 633 - 3
3x = 630
x = 210
So the three consecutive numbers we're looking for are: 210, 211, 212
You can just add the terms:
<span>(-x^2+9)+(-3x^2-11x+4) = -4x</span>² - 11x + 13
From the question we can deduce the formula to be 16 + 3n = 76
3n - 76 - 16
3n = 60
n = 20
20 is the answer.
Answer:
0.25 c to the second
Step-by-step explanation:
i think
Answer:
-2/3
Step-by-step explanation:
If you use the formula y2-y1/x2-x1 your answer will be -2/3