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Tpy6a [65]
3 years ago
15

1. find the degree of the monomial 6p^3q^2

Mathematics
2 answers:
allsm [11]3 years ago
4 0

Answer:

Part 1: 5

Part 2: 13t^2+17

Part 3:12n^3+15n^2

Part 4:9(2s-7)

Part 5: 25x^6-4

Part 6: (x^2+12x+35)

Part 7: 4z^2-12z+9

Step-by-step explanation:

Part 1: we have to find the degree of monomial 6p^3q^2

The degree of a polynomial is the highest degree of its monomials (individual terms) with non-zero coefficients.

The degree of monomial= 3+2=5

Option c is correct.

Part 2:  simplify (7t^2+9) + (6t^2+8)

(7t^2+9) + (6t^2+8)

(7t^2+6t^2)+(9+8)

13t^2+17

Option b is correct.

Part 3: simplify 3n(4n^2+5n)

3n(4n^2+5n)

By distributive property

12n^3+15n^2

Option a is correct.

Part 4: . factor 18s-63

18s-63

Taking 9 common from both terms

9(2s-7)

Option d is correct.

Part 5: simpler form of (5x^3+2)(5x^3-2)

(a-b)(a+b)=a^2-b^2

(5x^3+2)(5x^3-2)=(5x^3)^2-2^2=25x^6-4

Option d is correct.

Part 6:  simplify (x+7)(x+5)

(x+7)(x+5)=(x^2+5x+7x+35)=(x^2+12x+35)

Option a is correct.

Part 7: simplify (2z-3)^2

(a-b)^2=a^2+b^2-2ab

(2z-3)^2=(4z^2+9-2(2z)(3)=4z^2-12z+9

Option d is correct.

natali 33 [55]3 years ago
3 0

Theses are the answers for connections.

1.C

2.B

3.A

4.D

5.D

6.A

7.D

Hope this helps! Have a great day!

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