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Firdavs [7]
3 years ago
14

3. Given: ZCAT and ZDOG are right angles. What are ALL the conclusions that can be made?

Mathematics
1 answer:
lawyer [7]3 years ago
5 0

<em>Answer:</em>

<em>Can I see the question?</em>

<em>explanation: 772.malachi on insta</em>

<em />

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A bag contains 11 red M&amp;Ms, 8 green M&amp;Ms, and 6 blue M&amp;Ms.What is the ratio of blue M&amp;Ms to green M&amp;Ms?
Lana71 [14]

Answer:

The answer is 6/25 :8/25

4 0
3 years ago
Sneha went to a park 150m long and 80m wide. She took one complete round on its boundary. What is the distance covered by Sneha?
Blababa [14]

Answer:

460 m

Step-by-step explanation:

Boundary = perimeter

Perimeter = 2(length + width)

= 2(150 + 80)

= 2(230)

= 460 m

7 0
2 years ago
Read 2 more answers
Why is the percent increase from 45 to 75 not equal to the percent decrease from 75 to 452 Select three options
NNADVOKAT [17]

Answer:the ratio of the % increase has a different numerator from decrease

Step-by-step explanation:

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3 years ago
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Jessica is measuring two line segments. The first line segment is 30 cm long. The second line segment is 500 mm long. How long a
ElenaW [278]

Answer:

80 cm

Step-by-step explanation:

To find the length of both segments together, convert the lengths into one unit measure. Convert 500 mm  into centimeters by dividing it by 10. 500/10 = 50 cm. Now add 30 + 50 = 80 cm. The segment is 80 cm long.

7 0
3 years ago
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A cylinder shaped can needs to be constructed to hold 600 cubic centimeters of soup. The material for the sides of the can costs
PSYCHO15rus [73]

Answer:

the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm

Step-by-step explanation:

since the volume of a cylinder is

V= π*R²*L → L =V/ (π*R²)

the cost function is

Cost = cost of side material * side area  + cost of top and bottom material * top and bottom area

C = a* 2*π*R*L + b* 2*π*R²

replacing the value of L

C = a* 2*π*R* V/ (π*R²) + b* 2*π*R²  = a* 2*V/R + b* 2*π*R²

then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then

dC/dR = -2*a*V/R² + 4*π*b*R = 0

4*π*b*R = 2*a*V/R²

R³ = a*V/(2*π*b)

R=  ∛( a*V/(2*π*b))

replacing values

R=  ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm

then

L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm

therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm

5 0
4 years ago
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