Answer: The average was 9 years old find the average age of both groups is 10 years old.
Step-by-step explanation:
Formula foe average : 
Given : The first group of students consists of 10 and their average age was 13 years old.
i.e. 
(1)
The next group consisted of 30 students and their average was 9 years old.
i.e. 
(2)
Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400
Combined students of both groups (first and next group )= 10+30=40
Now , the average of both groups =
Hence, the average was 9 years old find the average age of both groups is 10 years old.
Answer:
x=1
Step-by-step explanation:
multiply both sides by 28 (it is the Least Common Multiple) which would bring your equation to be
7x-2= 4x+1
3x=3
x=1
Answer:
1) 78.87%
2) 99.7%
Step-by-step explanation:
The z-score for a normal distribution is given by:
1- The given data is:
σ = 4 years
μ = 50 years
For X = 45 and X =55
A z-score of -1.25 corresponds to the 10.57th percentile of a normal distribution, while a z-score of 1.25 is equivalent to the 89.44th percentile.
Therefore, the percentage of the alligators are between 45 and 55 years old is:
78.87% of alligators.
2- The given data is:
σ = 2 minutes
μ = 17 minutes
For X = 11 and X =23
A z-score of -3.0 corresponds to the 0.135th percentile of a normal distribution, while a z-score of 3.0 is equivalent to the 99.865th percentile.
Therefore, the percentage of people that should be seen by the doctor between 11 and 23 minutes is:
99.7% of people.
Answer:
y = -1x - 3
or
y = -x - 3
Step-by-step explanation:
Answer:
Total cost of dinner = P + 0.15p = 23
Step-by-step explanation:
Consider the information provided.
The cost of dinner at a restaurant is $P.
The tip offered for the service was, $0.15p.
The total of the cost of dinner and the tip offered for the service is:
T = P + 0.15p = 23
