Answer:
(x+6)(x+6)
(x+6)^2
Always remember this identity
(a+b)^2 = a^2 + b^2 + 2ab
So, Now take x=a , 6 =b
Substitute above values
x^2 + 36 +2(x)(6)
=x^2 +36 +12x
=x(x+12) +36
-2/3 times -2. You change -2 into -2/1 so you can multiply numerator to numerator and denominator to denominator. You will get 4/3 (negatives cancel out)
Answer:
multiply both sides by 30 in fraction form 30 / 30
& 570 for the blank square for numerator of 30
Step-by-step explanation:
Answer:
a. 8 gallons
b. (11-0.75t) gallons
Step-by-step explanation:
a. Here in this question, we are told that the total amount of fuel in the fuel tank is 11 gallons and the car consumes 0.75 gallon per hour. We are interested in knowing the amount of fuel left in the tank after driving for four hours.
We proceed as follows;
Since 0.75 gallon is consumed in an hour, the amount of fuel consumed in 4 hours would be the amount consumed in an hour * 4 hours
Mathematically, that would be 0.75 * 4 = 3 gallon
Now, the amount of fuel left is simply the difference between the initial amount of fuel in the tank minus the amount of fuel present after 4 hours.
That would be; 11 - 3 = 8 gallons
b. Like above, we want to know the amount of fuel left after t hours.
Since 0.75 is used up per hour, the amount used up in t hours would be 0.75 * t = 0.75t
Now, the amount of fuel that would be left in the tank would be the difference between what we had initially and what was used up.
Mathematically, that would be 11- 0.75t
49 pennants 1/3 x15 =30 so plus 1 and 2/3 that is 5 so it is 35 boom
