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ICE Princess25 [194]
2 years ago
6

Jayden is driving on a long road trip. He currently has 11 gallons of gas in his car. Each hour that he drives, his car uses up

0.75 gallons of gas. How much gas would be in the tank after driving for 4 hours? How much gas would be left after t hours?
Mathematics
1 answer:
DENIUS [597]2 years ago
4 0

Answer:

a. 8 gallons

b. (11-0.75t) gallons

Step-by-step explanation:

a. Here in this question, we are told that the total amount of fuel in the fuel tank is 11 gallons and the car consumes 0.75 gallon per hour. We are interested in knowing the amount of fuel left in the tank after driving for four hours.

We proceed as follows;

Since 0.75 gallon is consumed in an hour, the amount of fuel consumed in 4 hours would be the amount consumed in an hour * 4 hours

Mathematically, that would be 0.75 * 4 = 3 gallon

Now, the amount of fuel left is simply the difference between the initial amount of fuel in the tank minus the amount of fuel present after 4 hours.

That would be; 11 - 3 = 8 gallons

b. Like above, we want to know the amount of fuel left after t hours.

Since 0.75 is used up per hour, the amount used up in t hours would be 0.75 * t = 0.75t

Now, the amount of fuel that would be left in the tank would be the difference between what we had initially and what was used up.

Mathematically, that would be 11- 0.75t

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Nikolay [14]
To find the pre-image we work backwards. Since the coordinates one of the translated image is (5,-3) and this image was translated with the formula (x+4, y-2), then we can just work backwords. 
(x-4, y+2) --> (5-4,-3+2) -->(1,-1)
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5 0
3 years ago
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

4 0
3 years ago
Find the value of y that makes the equation y= 1/2x- 2 true when x=4 A. -4
olchik [2.2K]

Answer:

y = 0

Step-by-step explanation:

y =1/2(4)-2

y= 2-2

y=0

6 0
2 years ago
which best explains whether a triangle with side lengths 2 in., 5 in., and 4 in. is an acute triangle?
sdas [7]

Answer:

Obtuse triangle.

Step-by-step explanation:

Side a = 5

Side b = 2

Side c = 4

Angle ∠A = 108.21° = 108°12'36" = 1.88862 rad

Angle ∠B = 22.332° = 22°19'54" = 0.38976 rad

Angle ∠C = 49.458° = 49°27'30" = 0.86321 rad

Since one angle is above 90 degrees, the triangle is obtuse triangle.

This cannot be an acute triangle.

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One pipe fills a storage pool in 8 hours. A second pipe fills the same pool in 4 hours. When a third pipe is added and all three
steposvetlana [31]
The first pipe fills 1/8 of a pool in one hr.
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It takes the third pipe 1 hour and 36 minutes to fill it by itself.
7 0
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