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MAVERICK [17]
3 years ago
15

If the odds against Deborahs winning first prize in a chess tournament are 1 to 11 what is the probability of the event that she

will win first prize
Mathematics
1 answer:
Lemur [1.5K]3 years ago
7 0

Answer: \dfrac{11}{12}

Step-by-step explanation:

Given

The odds against winning in a chess tournament are 1 to 11.

Odds is defined as the ratio of the probability of occurrence to the non-occurrence of event.

\therefore \text{Probability that event will occur is P'=}\dfrac{1}{1+11}\\\\\Rightarrow P'=\dfrac{1}{12}

Probability of non-occurrence i.e. she wins the first prize is

\Rightarrow P=1-\dfrac{1}{12}\\\\\Rightarrow P=\dfrac{11}{12}

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3 years ago
Line A: y=-1/2x+3
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8 0
3 years ago
I need the answer please. Because I think i got mine wrong
Gekata [30.6K]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

• a^{-m} ⇔ \frac{1}{a^{m} }

• a^{0} = 1

• a^{m} × a^{n} ⇔ a^{(m+n)}

Given

(a)

8^{-2} = \frac{1}{8^{2} }

(b)

\frac{1}{3^{-3} } = 3³

(c)

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= \frac{1}{6^{4} }

7 0
3 years ago
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L = 103.078 m^2

B = 25 m^2

A = 128.078 m^2

3 0
3 years ago
Read 2 more answers
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