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2 years ago

Here are some summary statistics for the life spans of two breeds of cats.

Mathematics

1 answer:

stich3 [128]2 years ago

4 0

Answer:

D: Mittens

Step-by-step explanation:

We are given;

Population mean;

- Abyssinian: μ = 12

- Colorpoint shorthair: μ = 14

Population standard deviation;

- Abyssinian: σ = 1.5

- Colorpoint shorthair: σ = 1

Sample mean;

-Fluffy the Abyssinian: x¯ = 13

-Mittens the colorpoint shorthair; x¯ = 15

To find which cat had a longer lifespan, we need to find the z-score for both breeds and the one with the higher z-score is the one with longer lifespan.

Z-score formula is;

z = (x¯ - μ)/σ

For Fluffy the Abyssinian;

z = (13 - 12)/1.5

z = 0.667

For Mittens the colorpoint shorthair;

z = (15 - 14)/1

z = 1

Z-score of Mittens is higher and thus it has a longer lifespan.

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Suppose a normal distribution has a mean of 62 and a standard deviation of4. What is the probability that a data value is betwee

saw5 [17]

SOLUTION

From the given data the mean is 62 and standard deviation is 4

It is required to find the probability that a data value is between 57 and 62

That is:

$P(57\lt x\lt65)$

The z scores is calculated using:

$z=\frac{x-\mu}{\sigma}$

Using the x values it follows:

$z=\frac{57-62}{4}=-1.25$

Also,

$z=\frac{65-62}{4}=0.75$

Thus the required probability is:

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1 year ago

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Mkey [24]

Answer: 296 degrees

Step-by-step explanation:

Arc PRT is just the entire circumference - arc PT.

Since the 64 degree angle is a central angle, arc PT measures 64 degrees.

So arc PRT = 360 degree - 64 degree = 296 degrees.

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2 years ago

Leo needs 1010 red roses and 1515 pink daisies for every 55 bouquets he makes for a flower shop. Drag red roses and pink daisies

user100 [1]

[(1515+1010) / 55] x 33 = 1515

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Hope that answers it for you..

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2 years ago

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Vinvika [58]

The answer is 1 :)

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3 years ago

The area of a sector of an circle of a radius 5 cm, formed by an arc of length is 3.5cm. what is the answer

Natali5045456 [20]

Answer:

8.75cm²

Step-by-step explanation:

First we need to find the angle subtended by the arc

L = theta/360 * 2pir

3.5 = theta/360 * 2*3.14(5)

3.5 = theta/360 * 31.4

theta/360 = 3.5/31.4

theta/360 = 0.11146

theta = 0.11146 * 360

theta = 40.13 degrees

Area of the sector = theta/360 * pir^2

Area of the sector = 40.13/360 * 3.14*25

Area of the sector = 40.13/360 * 78.5

Area of the sector = 8.75cm

Hence the area of the sector is 8.75cm²

5 0

2 years ago