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Alex787 [66]
3 years ago
14

Which number(s) from the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, if any, will solve this equation?

Mathematics
1 answer:
8090 [49]3 years ago
8 0
Hello!

You solve this algebraically

2x + 3 = 5x - 3

Subtract 2x from both sides

3 = 3x - 3

Add 3 to both sides

6 = 3x

Divide both sides by 3

2 = x

The answer is A) 2

Hope this helps!
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Determine the place value of the digit 2 in the following whole number: 3,204,000
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Write 3 tens 9 ones in another way
Vsevolod [243]
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5 0
3 years ago
How any is?<br> 8m + 27 = 2m - 3 <br> with procedure and testing
givi [52]
8m+27= 2m-3
take 2m and subtract it from 8m, this gives you 6m. now your equation is 6m+27=-3.
subtract 27 from -3, this will make it 6m=-30.
divide 30 by 6. this gives you your answer. m=-5, because -30 divided by 6 equals -5.
now to test it you can plug -5 into the equation in place of M. 8 times -5 equals -40, plus 27 equals -13. 2 times -5 equals -10 plus -3 equals -13.
3 0
3 years ago
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1+1 equals what i don't know big prize i give all my brainy points i just graduated don't need this anymore
Marina86 [1]

\huge \mathbb \pink{HELLO }

\sf \green{1  + 1 \: is \: 2}

\huge \mathcal \orange{HAVE \: A \: GOOD \: DAY }

6 0
2 years ago
HELP PLEASE I NEED HELP
Vesna [10]

C. \: 8 \sqrt{3}✅

Step-by-step explanation:

\sqrt{192}  \\  =  \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3}  \\  =   \sqrt{ {2}^{2} \times  {2}^{2} \times  {2}^{2}    \times 3}  \\ =  \sqrt{ {8}^{2} \times 3 }    \\ =  8\sqrt{3}

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

4 0
3 years ago
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