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lozanna [386]
3 years ago
9

What is the variable to y = 64 (18)

Mathematics
2 answers:
Sladkaya [172]3 years ago
7 0

Answer:

y=1152

Step-by-step explanation:

PolarNik [594]3 years ago
7 0

Answer:

the varible equals 1152

Step-by-step explanation:

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Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

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Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

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3 years ago
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alukav5142 [94]
The correct answer is 3
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Step-by-step explanation:

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