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Nadya [2.5K]
3 years ago
12

The lot is `41` feet wide. The dividers are each `6` feet wide. Calculate how wide each space should be.

Mathematics
1 answer:
attashe74 [19]3 years ago
7 0

Answer:

94 feet.

Step-by-step explanation: if there is 4 sides you multiply 41 and 6 x 2

41 x 2 = 82

6 x 2 = 12

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2 years ago
A piece of wire 52cm long is cut into two parts , each of the wire is bent to form a square.If the sum of the area of the two sq
Gnom [1K]
Side lengths of the squares are x and y

4x+4y=52
divide both sides by 4 for simlicity
x+y=13


area is 89 so
x²+y²=89

ok

so

x+y=13
minus x both sides
y=13-x
sub that for y in other equation

x²+y²=89
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x²+x²-26x+169=89
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2x²-26x+80=0
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factor
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set to zero
x-8=0
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x-5=0
x=5


x=5 or 8

find y

y=13-x
13-8=5
13-5=8


each square has side length of 5 or 8
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5 0
3 years ago
You roll 2 six sided dice. What are the odds of rolling 2 sixes?
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You will have 1/6 odds
6 0
3 years ago
Read 2 more answers
Sec^6x (secxtanx) - sec^4x (secxtanx) = sec^5x tan^3x
Olegator [25]
Let E the expression of the left side of the equation:

E=\sec^6(x) (\sec (x)\tan (x)) - \sec^4(x) (\sec (x)\tan (x))\\\\
E=\sec^7(x)\tan(x)-\sec^5(x)\tan(x)\\\\
E=\sec^5(x)\tan(x)(\sec^2(x)-1)

We must know that \tan^2(x)+1=\sec^2(x)\iff \sec^2(x)-1=\tan^2(x). So, using in the equation above:

E=\sec^5(x)\tan(x)(\underbrace{\sec^2(x)-1}_{\tan^2(x)})\\\\
E=\sec^5(x)\tan(x)(\tan^2(x))\\\\
\boxed{E=\sec^5(x)\tan^3(x)}

Then, the equation is true.
3 0
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A clydesdale drinks about 120 gallons of water every 4 days at this rate about how many gallons of water does clydesdale drink i
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