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3 years ago

Solve for x. The polygons are similar. 4 2x – 12 5 10 10

Mathematics

1 answer:

Nataliya [291]3 years ago

4 0

Answer:

Step-by-step explanation: THIS WAS ACCIDENTAL! IM SO SORRY.

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Jake's family is moving to a new home. They pack 22 boxes in 1 5/6 hours. What is the average number of boxes per hour? Explain.

lbvjy [14]

12 boxes per hour is the answer

7 0

3 years ago

Dwayne buys ingredients to make a cake. He buys 1 1/2 pounds of flour, 12 ounces of coconut, and 1 1/4 pounds of sugar. What is

AVprozaik [17]

Answer:

3.05 or 31/2 pounds

56 ounces

Step-by-step explanation:

To find the total weight all the weights have to have the same units of measurements

It is either pounds is converted to ounces or ounces is converted to pounds

1. convert ounces to pound

1 ounce = 0.0625

12 ounces = 0.0625 x 12 = 0.75 pounds or 3/4

add together = 1 1/2 + 3/4 + 1 1/4 = $1\frac{1}{2} + \frac{3}{4} + 1\frac{1}{4}$

$2\frac{2 +3 + 1}{4}$ = $2\frac{6}{4}$ = 3 1/2

2. 16 ounces = 1 pound

flour = 16 x 1 1/2 = 24

sugar = 16 x 1 1/4 = 20

total = 24 + 20 + 12 = 56 ounces

6 0

3 years ago

A young sumo wrestler decided to go on a diet to gain weight rapidly. He gained weight at a rate of 5.5kg a month. After 11 mont

kondaur [170]

Answer:

$W(t)=5.5t+79.5$ .

Step-by-step explanation:

Please consider the complete question.

A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. He gained weight at a rate of 5.5 kilograms per month. After 11 months, he weighed 140 kilograms. Let W(t) denote the sumo wrestler's weight W(measured in kilograms) as a function of time t (measured in months).

Since wrestler gained weight at a rate of 5.5 kilograms per month, so slope of line be 5.5.

Now, we will use point-slope form of equation as:

$y-y_1=m(x-x_1)$ , where,

m = Slope

$(x_1,y_1)$ = Given point on the line.

Upon substituting coordinates of point (11,140) in above formula, we will get:

$y-140=5.5(x-11)$

$y-140=5.5x-60.5$

$y-140+140=5.5x-60.5+140$

$y=5.5x+79.5$

Therefore, our required function would be $W(t)=5.5t+79.5$ .

3 0

3 years ago

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per

ICE Princess25 [194]

Answer:

1.76% probability that in one hour more than 5 clients arrive

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.

This means that $\mu = 2$

What is the probability that in one hour more than 5 clients arrive

Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

We want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353$

$P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707$

$P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707$

$P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804$

$P(X = 4) = \frac{e^{-2}*2^{4}}{(4)!} = 0.0902$

$P(X = 5) = \frac{e^{-2}*2^{5}}{(5)!} = 0.0361$

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1353 + 0.2702 + 0.2702 + 0.1804 + 0.0902 + 0.0361 = 0.9824$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9824 = 0.0176$

1.76% probability that in one hour more than 5 clients arrive

8 0

3 years ago

Read 2 more answers

Which value of x makes the equation 3x = 36 true?<br> A. 10<br> B. 12<br> C. 14<br> D.16

oee [108]

Answer:

B. 12

x = 12

Also you can use mathpapa to help you with math.

7 0

3 years ago

Read 2 more answers

Solve for x. The polygons are similar. 4 2x – 12 5 10 10​

Solve for x. The polygons are similar. 4 2x – 12 5 10 10