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3 years ago

The shape is a rectangle, will you please help me find the angle measures of 1,2 and 3?

Mathematics

1 answer:

Ulleksa [173]3 years ago

8 0

Answer:

∠1 = ∠3 = 54°; ∠2 = 36°

Step-by-step explanation:

Each of the triangles is isosceles. Triangles opposite each other are congruent, so ∠2 is congruent to 36°.

∠2 and ∠3 are complementary, so ∠3 is 54°. Since ∠3 is congruent to ∠1, it, too, is 54°.

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What is the derivative of ln(lnx^3)

chubhunter [2.5K]

the derivative of ln(lnx^3) is $\frac{1}{x(lnx)}$ .

Step-by-step explanation:

Here we have to find the derivative of ln(lnx^3) , Let's find out:

We have , $ln(lnx^3)$ , Let's differentiate it w.r.t x :

⇒ $\frac{d(ln(lnx^3))}{dx}$

Let $lnx^3 = u$

⇒ $\frac{d(ln(u))}{dx}$

⇒ $\frac{1}{u} (\frac{d(u)}{dx} )$

⇒ $\frac{1}{u} (\frac{d(ln(x^3))}{dx} )$

Let $x^3=v$

⇒ $\frac{1}{u} (\frac{d(ln(v))}{dx} )$

⇒ $\frac{1}{u}(\frac{1}{v} ) (\frac{d(v)}{dx} )$

⇒ $\frac{1}{u}(\frac{1}{v} ) (\frac{d(x^3)}{dx} )$

⇒ $3x^2(\frac{1}{u})(\frac{1}{v} )$

Putting value of u & v we get:

⇒ $3x^2(\frac{1}{lnx^3})(\frac{1}{x^3} )$

⇒ $\frac{3}{x(lnx^3)}$ { $lnx^n = n(lnx)$ }

⇒ $\frac{3}{3x(lnx)}$

⇒ $\frac{1}{x(lnx)}$

Therefore , the derivative of ln(lnx^3) is $\frac{1}{x(lnx)}$ .

6 0

3 years ago

Please help i need to write out my work to so please tell me how to show it

Anarel [89]

For the first one write 9 divided by 2 gives your your radius an it’s 3.5. the formula is 2 x 3.14 x radius and that gives you 21.98.

the 2nd one is 2 x 3.14 x 9 = 56.52

the 3rd is 2 x 3.14 x 5= 31.4

formula is always 2 x 3.14 (or pie) x radius

to get your radius from your diameter you do your diameter divided by 2

3 0

2 years ago

Read 2 more answers

A bike wheel is shown. Chords I J and L K intersect at point M. The length of I M is 16 centimeters, the length of M J is 7 cent

levacccp [35]

Answer:

The diameter of the wheel is 32 centimeters

Step-by-step explanation:

we know that

The intersecting chords theorem states that the products of the lengths of the line segments on each chord are equal.

In this problem

$(LM)(MK)=(IM)(MJ)$