All categories

3 years ago

Find 3 different ratios that are equivalent to 7:3. Explain why these ratios are equivalent.

Mathematics

1 answer:

EastWind [94]3 years ago

7 0

14:6, 21:9, 28:12- they’re common multiples

You might be interested in

What is often found around the perimeter of a yard

sp2606 [1]

A fence I think

I hope this was the answer you were looking for

5 0

2 years ago

10 8 12 10 14 ? a. 16 b. 10 c. 12 d. 18

ahrayia [7]

Answer:

Step-by-step explanation:

10 8 subtract 2

8 12 add 4

12-10 subtract 2

10 14 add 4

Now we subtract 2

14-2 = 12

3 0

2 years ago

A manufacturer inspects 800 personal video players and finds that 796 of them have no defects. What is the experimental probabil

olga_2 [115]

Answer:

99.5

Step-by-step explanation:

You have to divide the amount of no video players with no defects by the total. So 796/800=0.995.

0.995 is the same as 99.5%

8 0

3 years ago

Read 2 more answers

Interior angles of quadrilaterals the sum of the four angles of any quadrilateral is 360

MaRussiya [10]

Answers:
angle x= E. 118°
angle m= 131°

explanation:
the sum of the four angles of any quadrilateral
is 360

8 0

2 years ago

There are two vendors at the fair sleeping snow cones for the same price. If the containers are completely filled and then level

aliya0001 [1]

Answer:

$d = 787.81cm^3$

Step-by-step explanation:

Given

See attachment for the containers

Required

The difference in the amount of snow cone they hold

The amount they hold is determined by calculating the volume of the containers.

The traditional snow cone has the following dimension

Shape: Cone

$r=4cm$ --- radius

$h = 13cm$ --- height

The volume is calculated as:

$Volume = \frac{1}{3} \pi r^2h$

So, we have:

$V_1 = \frac{1}{3} \pi * 4^2 * 13$

$V_1 = \frac{208}{3} \pi$

The snow cone in a cup has the following dimension

Shape: Cylinder

$r=8cm$ --- radius

$h = 5cm$ --- height

The volume is calculated as:

$Volume = \pi r^2h$

So, we have:

$V_2 = \pi *8^2 * 5$

$V_2 = \pi *320$

$V_2 = 320\pi$

The difference (d) in the amount they hold is:

$d = V_2 - V_1$

$d = 320\pi - \frac{208\pi}{3}$

Take LCM

$d = \frac{3*320\pi -208\pi}{3}$

$d = \frac{960\pi -208\pi}{3}$

$d = \frac{752\pi}{3}$

Take $\pi = 22/7$

$d = \frac{752}{3} * \frac{22}{7}$

$d = \frac{752 * 22}{3*7}$

$d = \frac{16544}{21}$

$d = 787.81cm^3$

4 0

2 years ago