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galben [10]
3 years ago
5

I NEED HELP ASAP!!!!!!!!

Mathematics
1 answer:
andreev551 [17]3 years ago
7 0

Step-by-step explanation:

slope =  \frac{rise}{run}  =  \frac{y2 - y1}{x2 - x1}  \\  =  \frac{ - 7 - 13}{5 - ( - 3)}  \\  =  \frac{ - 20}{8}  \\ =   \frac{ - 2 \times 10}{2 \times 4}  \\  =  \frac{ - 10}{4}  \\  =  \frac{ - 2 \times 5}{ 2  \times 2} =  \frac{5}{2}

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Is someone able to help me with this please I don't understand.
gulaghasi [49]

Answer:

d

Step-by-step explanation: if you pay attention to this answer its for points thanks

6 0
2 years ago
HELP PLZ! BRAINLIST WILL BE PICKED!
fomenos

Answer:

-0.9

Step-by-step explanation:

hope this helps lovely! lmk if you need an explanation!

3 0
3 years ago
Calculus 3 chapter 16​
o-na [289]

Evaluate \vec F at \vec r :

\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k

Compute the line element d\vec r :

d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt

Simplifying the integrand, we have

\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt

Then the line integral evaluates to

\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%7C2v%7C%20%20%3D%2012" id="TexFormula1" title=" |2v| = 12" alt=" |2v| = 12" align="absmi
BlackZzzverrR [31]

Answer:

v=6

Step-by-step explanation:

2v is positive so keep it

then 2v=12

v=6

8 0
3 years ago
Read 2 more answers
Help please will mark brainliest!
Nat2105 [25]

Answer:

Option B. Cosec θ = –5/3

Option C. Cot θ = 4/3

Option D. Cos θ = –4/5

Step-by-step explanation:

From the question given above, the following data were obtained:

Tan θ = 3/4

θ is in 3rd quadrant

Recall

Tan θ = Opposite / Adjacent

Tan θ = 3/4 = Opposite / Adjacent

Thus,

Opposite = 3

Adjacent = 4

Next, we shall determine the Hypothenus. This can be obtained as follow:

Opposite = 3

Adjacent = 4

Hypothenus =?

Hypo² = Opp² + Adj²

Hypo² = 3² + 4²

Hypo² = 9 + 16

Hypo² = 25

Take the square root of both side

Hypo = √25

Hypothenus = 5

Recall:

In the 3rd quadant, only Tan is positive.

Therefore,

Hypothenus = –5

Finally, we shall determine Sine θ, Cos θ, Cot θ and Cosec θ to determine which option is correct. This can be obtained as follow:

Opposite = 3

Adjacent = 4

Hypothenus = –5

Sine θ = Opposite / Hypothenus

Sine θ = 3/–5

Sine θ = –3/5

Cos θ = Adjacent / Hypothenus

Cos θ = 4/–5

Cos θ = –4/5

Cot θ = 1/ Tan θ

Tan θ = 3/4

Cot θ = 1 ÷ 3/4

Invert

Cot θ = 1 × 4/3

Cot θ = 4/3

Cosec θ = 1/ Sine θ

Sine θ = –3/5

Cosec θ = 1 ÷ –3/5

Invert

Cosec θ = 1 × –5/3

Cosec θ = –5/3

SUMMARY

Sine θ = –3/5

Cos θ = –4/5

Tan θ = 3/4

Cot θ = 4/3

Cosec θ = –5/3

Therefore, option B, C and D gives the correct answer to the question.

5 0
3 years ago
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