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Yakvenalex [24]
3 years ago
13

Mrs. Tart takes a survey in class. She discovers 60% of her students prefer using pens over pencils in class.

Mathematics
2 answers:
FrozenT [24]3 years ago
7 0

Answer:

20 students

Step-by-step explanation:

If,

60% = 12 students

∴ 1% = 12\60 students

∴ 100% = (12*100)\60 students

            = 20 students

{ easiest way for me}

Volgvan3 years ago
6 0

Answer:  D

Step-by-step explanation:

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Which expression is equivalent to
lisabon 2012 [21]
The answer is a) 2a+15b+11
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3 years ago
The base of a square measures 7 cm, and its height measures 6 centimeters. How tall is your area?
Alexxandr [17]

Answer:

42cm^{2}

Step-by-step explanation:

In order to find the area of a square you take the base and multiply it by the height.

Base x Height = Area

In this case you have 7cm as the base and 6cm as the height.

All you have to do after that is multiply the two together.

Make sure that you remember to put the unit (cm) and make sure that it is cm^{2} because some teachers are uptight about that stuff.

Hope this helped!

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5 0
3 years ago
Helppppp what is 48 times the power of x , If x= 1/5
sweet-ann [11.9K]

on my calculator 48^1/5 equals 2.168943542

but out of a fraction 1/5 equals 0.2  ( they both equal the same thing)


2.168943542

6 0
3 years ago
Read 2 more answers
I need help with this
n200080 [17]
Multiplication, addition, subtraction
8 0
2 years ago
Read 2 more answers
If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -,
S_A_V [24]
Taking y=y(x) and differentiating both sides with respect to x yields

\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0

Solving for the first derivative, we have

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x}y

Differentiating again gives

\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0

Solving for the second derivative, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{3+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}y=-\dfrac{3+\frac{9x^2}{y^2}}y=-\dfrac{3y^2+9x^2}{y^3}

Now, when x=1 and y=2, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}\bigg|_{x=1,y=2}=-\dfrac{3\cdot2^2+9\cdot1^2}{2^3}=\dfrac{21}8\approx2.63
3 0
3 years ago
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